Mysql正向工程sql重复外键约束

我不知道多少SQL，我通过MySQL工作台使用建模生成了它。我总是得到一个

错误代码：1826。当我尝试导入通过workbench的正向工程生成的SQL时，重复外键约束名称“post_id”

。如果有人能把我救出来。我不是从零开始编写的。我只是做了一个ERD并生成了一个SQL

其他信息，此行将触发错误

如果不存在，则创建表测试

另外，MySQL工作台和服务器都是8.0.19版本

下面是生成的SQL

-- MySQL Script generated by MySQL Workbench
-- Tue Mar 31 21:51:19 2020
-- Model: New Model    Version: 1.0
-- MySQL Workbench Forward Engineering

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_ENGINE_SUBSTITUTION';

-- -----------------------------------------------------
-- Schema testing
-- -----------------------------------------------------

-- -----------------------------------------------------
-- Schema testing
-- -----------------------------------------------------
CREATE SCHEMA IF NOT EXISTS `testing` DEFAULT CHARACTER SET utf8 ;
USE `testing` ;

-- -----------------------------------------------------
-- Table `testing`.`users`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `testing`.`users` (
  `userid` DOUBLE NOT NULL,
  `username` VARCHAR(100) NULL,
  `email` VARCHAR(100) NULL,
  `name` VARCHAR(100) NULL,
  `handle` VARCHAR(45) NULL,
  `quote` LONGTEXT NULL,
  `last_updated` DATE NULL,
  PRIMARY KEY (`userid`))
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `testing`.`posts`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `testing`.`posts` (
  `post_id` DOUBLE NOT NULL,
  `user_id` DOUBLE NOT NULL,
  `description` LONGTEXT NULL,
  `images` LONGTEXT NULL,
  `tags` LONGTEXT NULL,
  `last_updated` DATE NULL,
  PRIMARY KEY (`post_id`),
  INDEX `user_id_idx` (`user_id` ASC) VISIBLE,
  CONSTRAINT `user_id`
    FOREIGN KEY (`user_id`)
    REFERENCES `testing`.`users` (`userid`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `testing`.`comments`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `testing`.`comments` (
  `comment_id` DOUBLE NOT NULL,
  `post_id` DOUBLE NOT NULL,
  `description` LONGTEXT NULL,
  `images` LONGTEXT NULL,
  `last_updated` DATE NULL,
  PRIMARY KEY (`comment_id`),
  INDEX `post_id_idx` (`post_id` ASC) VISIBLE,
  CONSTRAINT `post_id`
    FOREIGN KEY (`post_id`)
    REFERENCES `testing`.`posts` (`post_id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `testing`.`post_likes`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `testing`.`post_likes` (
  `plike_id` DOUBLE NOT NULL,
  `post_id` DOUBLE NOT NULL,
  `user_id` DOUBLE NOT NULL,
  `type` INT NULL,
  PRIMARY KEY (`plike_id`),
  INDEX `post_id_idx` (`post_id` ASC) VISIBLE,
  INDEX `user_id_idx` (`user_id` ASC) VISIBLE,
  CONSTRAINT `post_id`
    FOREIGN KEY (`post_id`)
    REFERENCES `testing`.`posts` (`post_id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `user_id`
    FOREIGN KEY (`user_id`)
    REFERENCES `testing`.`users` (`userid`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `testing`.`comment_likes`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `testing`.`comment_likes` (
  `clike_id` DOUBLE NOT NULL,
  `comment_id` DOUBLE NOT NULL,
  `user_id` DOUBLE NOT NULL,
  `type` INT NULL,
  PRIMARY KEY (`clike_id`),
  INDEX `comment_id_idx` (`comment_id` ASC) VISIBLE,
  INDEX `user_id_idx` (`user_id` ASC) VISIBLE,
  CONSTRAINT `comment_id`
    FOREIGN KEY (`comment_id`)
    REFERENCES `testing`.`comments` (`comment_id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `user_id`
    FOREIGN KEY (`user_id`)
    REFERENCES `testing`.`users` (`userid`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;


SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

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根据与@p.Salmon的讨论，表明FK名称重复。因此，我通过ERD调整了FK名称，并生成了一个新的SQL文件。因此，基本上，我避免使用相同的FK名称，瞧，这是可行的

见下文

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我建议在您的ui中提供可见索引，但在您的mysql版本中不提供。如果您正在使用mysqlworkbench，请关闭此行为（请参阅mysqlworkbench手册），您的意思是取消选中“可见”复选框吗？是吗，但出现了相同的错误？然后我猜您必须手动编辑.sql文件您的意思是删除sa“可见”部分吗？