MySQL按不同表中的多列求和排序

我有三张桌子：

使用者 喜欢 交易 我需要获得每个用户的like.like和transaction.transaction的总和，然后根据结果对其进行排序

我能够为用户和喜欢的人做这件事：

select users.*, sum(likes.like) as points
from `users`
inner join `likes` on `likes`.`user_id` = `users`.`id`
group by `users`.`id`
order by points desc

然后我添加了如下事务表：

select users.*, (sum(likes.like)+sum(transactions.`transaction`)) as points
from `users`
inner join `likes` on `likes`.`user_id` = `users`.`id`
inner join `transactions` on `transactions`.`user_id` = `users`.`id`
group by `users`.`id`
order by points desc

这是错误的结果

我希望看到：

| id | name  | points |
|----|-------|--------|
| 3  | Three | 12     |
| 1  | One   | 7      |
| 2  | Two   | 5      |

但是，请记住：

| id | name  | points |
|----|-------|--------|
| 3  | Three | 12     |
| 1  | One   | 6      |
| 2  | Two   | 5      |

那么，如何按喜欢和交易对用户进行排序呢

---

谢谢大家!

由于

事务

和

喜欢

之间没有1对1的关系，我认为您需要使用子查询：

select users.*,
    (select sum(points) from likes where user_id = users.id) as points,
    (select sum(transaction) from transactions where user_id = users.id) as transactions
from users
order by points desc

在对要求进行更多解释后更新了：

select users.*,
    (select sum(points) from likes where user_id = users.id) +
    (select sum(transaction) from transactions where user_id = users.id) as points
from users
order by points desc

---

请加上你得到的结果和期望的结果。我不明白喜欢的表格。你们能解释一下它的作用吗？比如说，用户喜欢这个页面的次数有多少次是错误的。在你的结果1中，有8分，但必须是7（喜欢的3+8，喜欢的-1），所以你只需要把这两个加在一起。我将更新示例。我猜你的意思是喜欢的3+5…看起来像是工作，谢谢！对性能有什么建议吗？您应该在

用户id

列中为

交易

和

喜欢

| id | name  | points |
|----|-------|--------|
| 3  | Three | 12     |
| 1  | One   | 6      |
| 2  | Two   | 5      |

select users.*,
    (select sum(points) from likes where user_id = users.id) as points,
    (select sum(transaction) from transactions where user_id = users.id) as transactions
from users
order by points desc

select users.*,
    (select sum(points) from likes where user_id = users.id) +
    (select sum(transaction) from transactions where user_id = users.id) as points
from users
order by points desc