Mysql 检查主键SQL是否不存在行

我有四张桌子

每个蛋糕上正好有3个小点和1个糖霜

我想查询数据库，得到所有有1块糖霜和3块糖霜的蛋糕，其中糖霜和任何糖霜都没有消耗='1'

因此，让我们用psuedo插入数据： 插入冰桌（香草，0），（巧克力，0）

现在我有香草糖衣和红色、蓝色、绿色的糖衣，还有巧克力糖衣和橙色、紫色、粉色的糖衣

当我运行查询时，我希望它返回

CAKES
cake1
cake2

只有当蛋糕中没有已消耗的部分时，所以即使一个洒点被标记为已消耗，我也希望从查询中忽略整个蛋糕。 下面的查询正是针对结冰的查询

SELECT CAKE
FROM CAKETABLE as c
INNER JOIN (SELECT * FROM ICINGTABLE WHERE CONSUMED = '0') as i
ON c.ICING = i.ICING;

要不是洒了水，我就有麻烦了。如果使用与上述相同的技术，我的查询将返回：

CAKE
cake1
cake1
cake1
cake2
cake2
cake2

我可以使用DISTINCT消除这一点，但它仍然是不正确的，因为当我需要相反的功能时，如果任何Spreading已使用='0'，它将在列表中显示该蛋糕（仅当所有Spreading已使用='0'时才显示蛋糕）

---

如果有人有更好的标题名称，我们将不胜感激。我想不出任何描述性和简短的东西。

您可以使用

不存在

来要求不使用结冰或洒水：

select  cake
from    caketable c
where   not exists
        (
        select  *
        from    icingtable i
        where   i.cake = c.cake
                and i.consumed = '1'
        )
        and not exists
        (
        select  *
        from    sprinkletable s
        where   s.cake = c.cake
                and s.consumed = '1'
        )

---

假设一块蛋糕始终有三个喷水点，您可以

按

蛋糕分组，并使用

HAVING

过滤没有三个未使用喷水点的蛋糕：

SELECT CAKE
FROM CAKETABLE as C
INNER JOIN (
    SELECT * FROM ICINGTABLE WHERE CONSUMED = '0'
) as I ON C.CAKE = I.CAKE
INNER JOIN (
    SELECT CAKE FROM SPRINKLETABLE 
    WHERE CONSUMED = '0'
    GROUP BY CAKE
    HAVING COUNT(*) = 3
) as S ON C.CAKE = S.CAKE;

---

我认为以下内容符合您的要求：

select ct.cake
from caketable ct join
     reservedsprinkle rs
     on ct.cake = rs.cake join
     sprinkletable st
     on rs.sprinkle = st.sprinkle join
     icingtable it
     on ct.cake = it.cake
where it.consumed = 0
group by ct.cake
having count(distinct rs.sprinkle) = 3 and
       sum(case when st.consumed = 1 then 1 else 0 end) = 0

---

这是按蛋糕分组，然后将大多数条件放入HAVING子句中。通过数据库设计，看起来蛋糕只能有一层糖霜。我假设蛋糕在蛋糕表中是唯一的。

ICINGTABLE（表一）没有蛋糕？你有N个c.CAKE=i.CAKE；，但在您提供的模式中，CAKE不是ICingTable中的列，CAKE是谎言。“也许是黑色台面？哈哈！那是个玩笑。”--GLaDOS@james31rock你是对的，我错了。它应该在结冰时接合，因为可凝固和结冰台都有结冰。

SELECT CAKE
FROM CAKETABLE as C
INNER JOIN (
    SELECT * FROM ICINGTABLE WHERE CONSUMED = '0'
) as I ON C.CAKE = I.CAKE
INNER JOIN (
    SELECT CAKE FROM SPRINKLETABLE 
    WHERE CONSUMED = '0'
    GROUP BY CAKE
    HAVING COUNT(*) = 3
) as S ON C.CAKE = S.CAKE;

select ct.cake
from caketable ct join
     reservedsprinkle rs
     on ct.cake = rs.cake join
     sprinkletable st
     on rs.sprinkle = st.sprinkle join
     icingtable it
     on ct.cake = it.cake
where it.consumed = 0
group by ct.cake
having count(distinct rs.sprinkle) = 3 and
       sum(case when st.consumed = 1 then 1 else 0 end) = 0