Mysql 每个日期加载前5条记录

我有一个表格，里面有不同用户的日期测验分数。我想为每个日期加载前5名得分手

表示例create语句：

我尝试过的查询：

实际输出：每个日期只显示一个最佳得分者

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想要输出前5名，或者说每个日期需要10条记录。

请参考此查询，它不完整，但希望能有所帮助

SELECT SCORE
FROM table
WHERE date='somedate'
ORDER BY SCORE DESC LIMIT 5

这就是如何在oracle sql中找到问题的解决方案。

请尝试下面的方法

     SELECT subscriber.msisdn AS msisdn,subscriber.name AS name,subscriber.gender AS gender,tmp2.score AS score,tmp2.date AS winning_date 
      FROM subscriber inner join
      (select msisdn,date, score, ROW_NUMBER() OVER(PARTITION BY date ORDER BY score DESC) AS Row
       FROM subscriber_score 
       WHERE date > '2014-10-10' AND date < '2014-11-10' GROUP BY date) 
      tmp 
     on subscriber.msisdn=tmp.msisdn and tmp.row<=5

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我认为您可以使用变量为每行分配一个行号，然后为每个日期筛选前5名

SELECT  s.name AS name,
        s.gender AS gender,
        s.msisdn,
        ss.date,
        ss.score
FROM    (   SELECT  ss.msisdn,
                    ss.score,
                    @r:= CASE WHEN ss.Date = @d THEN @r + 1 ELSE 1 END AS RowNum,
                    @d:= ss.date AS winning_date
            FROM    subscriber_score AS ss
                    CROSS JOIN (SELECT @d:= '', @r:= 0) AS v
            WHERE   ss.date > '2014-10-10' 
            AND     ss.date < '2014-11-10'
            ORDER  BY ss.Date, ss.Score DESC
        ) AS ss
        INNER JOIN Subscriber AS s
            ON s.msisdn = ss.msisdn
WHERE   ss.RowNum <= 5;

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5个什么？编辑您的问题并提供示例输出和所需结果。这只提供一个日期的记录。我需要为所选日期范围内的每个日期提供5条记录。请验证您是否有该特定日期的5条记录。但他的问题也标记为SQL，否则他必须在问题中声明他在MySQL中查找结果。这就是为什么@amenadiel我在我的查询下面写道，如何在oracle SQL中执行此操作这是正确的方法在MySQL中执行，尽管它可能需要一些微调，比如用开始日期初始化@d。谢谢，这似乎是正确的。让我适应我的场景，稍后再告诉你。他使用的是MySQL，没有OVER/PARTITIONMySQL@nitubansal就连我也写了同样的高等级查询。。。我想他应该提到，他正在mysql中寻找结果，他的问题也用sql标记，可能是任何sqlnowhere编写的查询都应该是sql或mysql，这种方法没有任何错误，可能对寻找sql方法的人有用。

select  bc.msisdn msisdn,bc.name name,bc.gender gender,ab.score score,ab.date winning_date
    (
       select msisdn,date,score,
       dense_rank() over (partition by date order by score desc) rnk 
        from subscriber_score
     ) ab,subscriber bc
 where bc.msisdn=ab.msisdn and ab.rnk<=5 
 order by winning_date     ;

     SELECT subscriber.msisdn AS msisdn,subscriber.name AS name,subscriber.gender AS gender,tmp2.score AS score,tmp2.date AS winning_date 
      FROM subscriber inner join
      (select msisdn,date, score, ROW_NUMBER() OVER(PARTITION BY date ORDER BY score DESC) AS Row
       FROM subscriber_score 
       WHERE date > '2014-10-10' AND date < '2014-11-10' GROUP BY date) 
      tmp 
     on subscriber.msisdn=tmp.msisdn and tmp.row<=5

SELECT  s.name AS name,
        s.gender AS gender,
        s.msisdn,
        ss.date,
        ss.score
FROM    (   SELECT  ss.msisdn,
                    ss.score,
                    @r:= CASE WHEN ss.Date = @d THEN @r + 1 ELSE 1 END AS RowNum,
                    @d:= ss.date AS winning_date
            FROM    subscriber_score AS ss
                    CROSS JOIN (SELECT @d:= '', @r:= 0) AS v
            WHERE   ss.date > '2014-10-10' 
            AND     ss.date < '2014-11-10'
            ORDER  BY ss.Date, ss.Score DESC
        ) AS ss
        INNER JOIN Subscriber AS s
            ON s.msisdn = ss.msisdn
WHERE   ss.RowNum <= 5;