Mysql 如何为此编写sql查询:
我想选择所有没有值“c”的ID 它不会简单地通过以下查询工作:Mysql 如何为此编写sql查询:,mysql,sql,tsql,Mysql,Sql,Tsql,我想选择所有没有值“c”的ID 它不会简单地通过以下查询工作: mysql> select * from table3 order by id; +------+-------+ | id | value | +------+-------+ | 1 | a | | 1 | b | | 1 | c | | 1 | d | | 2 | a | | 2 | b | | 3 | a | |
mysql> select * from table3 order by id;
+------+-------+
| id | value |
+------+-------+
| 1 | a |
| 1 | b |
| 1 | c |
| 1 | d |
| 2 | a |
| 2 | b |
| 3 | a |
| 3 | b |
| 3 | c |
| 4 | a |
| 4 | b |
+------+-------+
mysql>从表3中选择不同的id,其中值为'c';
+------+
|身份证|
+------+
| 1 |
| 2 |
| 3 |
| 4 |
+------+
我只需要返回2和4
谢谢你的关注 这对你有用
mysql> select distinct id from table3 where value <> 'c';
+------+
| id |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
+------+
这对你有用
mysql> select distinct id from table3 where value <> 'c';
+------+
| id |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
+------+
是的,实际表格有10000多行,如果没有找到更合适的答案,我会在以后标记你的答案,谢谢是的,实际表格有10000多行,如果没有找到更合适的答案,我会在以后标记你的答案,谢谢
select distinct id
from table3 t
where not exists
(select 1 from table3 where value = 'c' and id = t.id)