创建一个产生嵌套JSON数组对象的MySQL过程

我需要在mysql中创建一个存储过程，从DB中获取一些字段，并创建一个整洁的json对象：

首先，我创建一个json对象，如下所示：

{
    "form": "Exams tests",
    "version": "v3.001.01",
    "questions": []
}

其次是一个json数组对象，如下所示：

{[
        {
            "ordem": 1,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
        }
        {
            "ordem": 2,
            "num_questions": 2,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
            "question2": "Where do you live?"
            "answer2": "I live in Boston."
        }
        {
            "ordem": 3,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 23 years old."
        }
]}

{
    "form": "Exams tests",
    "version": "v3.001.01",
    "questions": {[
        {
            "ordem": 1,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
        }
        {
            "ordem": 2,
            "num_questions": 2,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
            "question2": "Where do you live?"
            "answer2": "I live in Boston."
        }
        {
            "ordem": 3,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 23 years old."
        }
    ]}
}

结果查询如下所示：

{[
        {
            "ordem": 1,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
        }
        {
            "ordem": 2,
            "num_questions": 2,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
            "question2": "Where do you live?"
            "answer2": "I live in Boston."
        }
        {
            "ordem": 3,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 23 years old."
        }
]}

{
    "form": "Exams tests",
    "version": "v3.001.01",
    "questions": {[
        {
            "ordem": 1,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
        }
        {
            "ordem": 2,
            "num_questions": 2,
            "question1": "How old are you?"
            "answer1": "I'm 18 years old."
            "question2": "Where do you live?"
            "answer2": "I live in Boston."
        }
        {
            "ordem": 3,
            "num_questions": 1,
            "question1": "How old are you?"
            "answer1": "I'm 23 years old."
        }
    ]}
}

我在尝试将嵌套json数组插入json对象时出错

我将json_对象与json_ArrayAg连接在一起，如下所示：

{
    "name": "Moon",
    "resume": "This is a resume.",
    "dt_ini": "2018-09-01",
    "dt_end": null,
    "cases": [
        {
            "unit": "unit 1",
            "unit_id": 10
        },
        {
            "unit": "unit 2",
            "unit_id": 290
        },
        {
            "unit": "unit 3",
            "unit_id": 44
        },
        {
            "unit": "unit 4",
            "unit_id": 108
        }
    ]
}

最终结果是：

CREATE DEFINER=`root`@`localhost` PROCEDURE `get_list_case`(
IN `code` int,
IN `base_code` int)
BEGIN

    DECLARE json TEXT DEFAULT '';

    SELECT JSON_OBJECT(
        'name', v.name, 
        'dt_ini', v.dt_ini, 
        'dt_end', v.dt_end, 
        'resumo', v.resumo,
        'cases', ( select json_arrayagg(json_object(
                                'unit_id',`tb_unit`.`unit_id`,
                                'unit',`tb_unit`.`unit`))
                            from tb_unit_case
                                INNER JOIN tb_unit ON tb_unit_case.unid_code = tb_unit.unit_id
                            WHERE tb_unit_case.case_code = code)
    ) INTO json
    FROM v_case AS v
    WHERE v.code = code and v.base_code = base_code;
    
    SELECT json;
    
END

---

请让我们看看代码，一封信很好，但你最好给我们看代码。你可以在这里找到答案：这是否回答了你的问题？我现在明白了。我将JSON_ArrayAg与JSON_对象一起使用。只需一次选择即可完成所有步骤，如下所示：选择JSON_对象“form”，v.form_名称，“version”，v.version，“questions”，选择JSON_ArrayAgjson_对象“ordem”，tb_questions.order，'num_questions'，tb_questions.num'question1'，tb_questions.question1'answer1'，tb_questions.answer1从tb_questions转换成json从v_case作为v；