Mysql 在selectquerycakephp中选择

我有两张桌子

1. feeds => id,name 2. feed_locations => id, feed_id, latitude,longitude,location_name 这是我的cakephp代码

    $radious    =   '10';
    $this->paginate = array(
        'joins' => array(
            array('table' => 'feed_locations',
                'alias' => 'FeedLocation',
                'type' => 'LEFT',
                'conditions' => array(
                    'FeedLocation.feed_id = Feed.id',
                )
            )
        ),
        'limit'      => 10,             
        'fields' => array('id','name','(3959 * acos (cos ( radians('.$lat.') ) * cos( radians( FeedLocation.latitude ) ) * cos( radians( FeedLocation.longitude ) - radians('.$lng.') ) + sin ( radians('.$lat.') ) * sin( radians( FeedLocation.latitude )))) AS `distance`'),
        'recursive' => -1,
        'order'    =>  'distance ASC',
        'group' => 'Feed.id HAVING distance <'.$radious          
    );

我的查询正在运行，但发出以下消息：

例如，如果一个单一的饲料有10个位置，如1米，2米，3米，4米，5米，10米，100米的距离。我想找到5米距离的所有馈源，然后它工作，但它告诉我，这个馈源有5米。距离我，但结果应该是1米的距离。 我想用cakephp语法实现这个mysql查询

SELECT 
    a.id,
    a.name,
    a.distance,
    a.location_count
    FROM
      (SELECT
        `Feed`.`id`, 
        `Feed`.`name`, 
        (3959 * acos (cos ( radians(40.7127837) ) * 
        cos( radians( FeedLocation.latitude ) ) * 
        cos( radians( FeedLocation.longitude ) -
        radians(-74.00594130000002) ) + sin ( radians(40.7127837) ) * 
        sin( radians( FeedLocation.latitude )))) AS `distance`, 
          (Select COUNT(id) 
             FROM feed_locations 
             WHERE feed_id = `Feed`.`id`) AS `location_count` 
             FROM `feeds` AS `Feed` 
             LEFT JOIN `feed_locations` AS `FeedLocation` ON (`FeedLocation`.`feed_id` = `Feed`.`id`) 
        ORDER BY `distance` ASC) AS a
        GROUP BY a.id HAVING distance < 10;

---

这个查询给了我确切的结果。请让我知道如何在cakephp中使用此查询。在cakephp中，您还可以使用准备好的语句，在这些语句中，您可以使用SQL创建查询，请查看文档：

我已经尝试了此代码

function paginate($conditions, $fields, $order, $limit, $page, $recursive, $extra){
    $db         = $this->getDataSource();
    $modelName  =   $this->alias;   
    $result = $db->fetchAll(
        'SELECT 
        '.$modelName.'.id,
        '.$modelName.'.name,
        '.$modelName.'.distance,
        '.$modelName.'.location_count
        FROM
          (SELECT
            `Feed`.`id`, 
            `Feed`.`name`, 
            (3959 * acos (cos ( radians(40.7127837) ) * 
            cos( radians( FeedLocation.latitude ) ) * 
            cos( radians( FeedLocation.longitude ) -
            radians(-74.00594130000002) ) + sin ( radians(40.7127837) ) * 
            sin( radians( FeedLocation.latitude )))) AS `distance`, 
              (Select COUNT(id) 
                 FROM feed_locations 
                 WHERE feed_id = `Feed`.`id`) AS `location_count` 
                 FROM `feeds` AS `Feed` 
                 LEFT JOIN `feed_locations` AS `FeedLocation` ON (`FeedLocation`.`feed_id` = `Feed`.`id`) 
            ORDER BY `distance` ASC) AS '.$modelName.'
            GROUP BY '.$modelName.'.id HAVING distance < 10;'
    );  
    return $result;
}

它对我非常有效。

---

我已在模型中管理此查询。我在模型中创建了一个函数paginate，并提到了这个查询。然后它会自动分页数据。

我不理解这种类型的查询如何实现

function paginate($conditions, $fields, $order, $limit, $page, $recursive, $extra){
    $db         = $this->getDataSource();
    $modelName  =   $this->alias;   
    $result = $db->fetchAll(
        'SELECT 
        '.$modelName.'.id,
        '.$modelName.'.name,
        '.$modelName.'.distance,
        '.$modelName.'.location_count
        FROM
          (SELECT
            `Feed`.`id`, 
            `Feed`.`name`, 
            (3959 * acos (cos ( radians(40.7127837) ) * 
            cos( radians( FeedLocation.latitude ) ) * 
            cos( radians( FeedLocation.longitude ) -
            radians(-74.00594130000002) ) + sin ( radians(40.7127837) ) * 
            sin( radians( FeedLocation.latitude )))) AS `distance`, 
              (Select COUNT(id) 
                 FROM feed_locations 
                 WHERE feed_id = `Feed`.`id`) AS `location_count` 
                 FROM `feeds` AS `Feed` 
                 LEFT JOIN `feed_locations` AS `FeedLocation` ON (`FeedLocation`.`feed_id` = `Feed`.`id`) 
            ORDER BY `distance` ASC) AS '.$modelName.'
            GROUP BY '.$modelName.'.id HAVING distance < 10;'
    );  
    return $result;
}