Mysql 按两个日期列对视图排序，并添加排名列

我有一个类似下面的mysql表

id name firstDate secondDate == ===== ========= ========== A1 Carol 2000-07-24 1956-07-24 A2 Victor 2000-07-24 1980-01-13 A3 Paul 1999-12-10 1985-01-10 A4 Mia 2000-06-17 1945-10-22 A5 Luke 2000-07-24 1960-03-19 id名称firstDate secondDate == ===== ========= ========== A1卡罗尔2000-07-241956-07-24 A2维克多2000-07-241980-01-13 A3保罗1999-12-10 1985-01-10 A4 Mia 2000-06-17 1945-10-22 A5卢克2000-07-241960-03-19 我需要创建具有以下格式的视图：

按firstDate列升序排序

如果两个或多个记录在firstDate列上具有相同的值，则这些记录将使用secondDate列来决定将哪个记录放在第一、第二位，依此类推

第二个日期列之后将添加列秩，该列具有连续数字

像这样

id name firstDate secondDate rank == ===== ========= ========== ==== A3 Paul 1999-12-10 1985-01-10 1 A4 Mia 2000-06-17 1945-10-22 2 A1 Carol 2000-07-24 1956-07-24 3 A5 Luke 2000-07-24 1960-03-19 4 A2 Victor 2000-07-24 1980-01-13 5 id名称firstDate第二个日期等级 == ===== ========= ========== ==== A3保罗1999-12-10 1985-01-10 1 A4 Mia 2000-06-17 1945-10-22 2 A1卡罗尔2000-07-241956-07-243 5卢克2000-07-24 1960-03-19 4 A2维克多2000-07-241980-01-13 5 作为

试试这个

    SET @rank := 0;
    SELECT * , @rank := @rank + 1 AS rank FROM
    (
    SELECT id , name  ,  firstDate  , secondDate
    from table1
     ORDER BY firstDate  asc, secondDate asc
    ) zz

还是这个

   SELECT * , @rank := @rank + 1 AS rank FROM
  (
  SELECT id , name  ,  firstDate  , secondDate
  from table1
   ORDER BY firstDate  asc, secondDate asc
   ) zz, (SELECT @rank := 0) z;

---

你可以简化echo\u Me的回答：

SET @rank := 0;
SELECT id , name  ,  firstDate  , secondDate , @rank := @rank + 1 AS rank 
FROM table1
ORDER BY firstDate  asc, secondDate asc

看