MySQL选择distinct，但仅当所有第二列=1时？

我希望这只是不返回任何东西。我该怎么做

mysql> select distinct (search_num), complete from Table where complete = '1';
+------------+----------+
| search_num | complete |
+------------+----------+
|       1825 |        1 |
+------------+----------+

因为实际上有一（或多）行仍然是0，如图所示：

mysql> select distinct (search_num), complete from Table;
+------------+----------+
| search_num | complete |
+------------+----------+
|       1825 |        1 |
|       1825 |        0 |
+------------+----------+

---

我该怎么做呢？

这里的一种方法是通过

search_num

进行聚合，然后断言出现的唯一

complete

值是1

mysql> select distinct (search_num), complete from Table where complete = '1';
+------------+----------+
| search_num | complete |
+------------+----------+
|       1825 |        1 |
+------------+----------+

SELECT search_num
FROM yourTable
GROUP BY search_num
HAVING MIN(complete) = MAX(complete) AND MIN(complete) = 1;

---

这里的一种方法是通过

search\u num

进行聚合，然后断言出现的唯一

complete

值是1

SELECT search_num
FROM yourTable
GROUP BY search_num
HAVING MIN(complete) = MAX(complete) AND MIN(complete) = 1;

---

distinct

不是函数，它是

select distinct

的一部分，适用于整个选定行。跳过那些额外的括号以使代码更清晰，即只需编写

select distinct search\u num，complete…

distinct

不是一个函数，它是

select distinct

的一部分，并应用于整个选定行。跳过那些额外的括号以使代码更清晰，即只需写

选择distinct search\u num，complete…

。