MySQL Order By in UNION语句
我有这个MySQL查询,查询没有给出任何错误MySQL Order By in UNION语句,mysql,Mysql,我有这个MySQL查询,查询没有给出任何错误 $sql_i = "(SELECT fld.product_id AS product_id, inh_pr.naam AS productnaam, fld.aantal AS aantal, '' AS afmeting, '' AS proces, '' AS gewicht,
$sql_i = "(SELECT
fld.product_id AS product_id,
inh_pr.naam AS productnaam,
fld.aantal AS aantal,
'' AS afmeting,
'' AS proces,
'' AS gewicht,
'' AS kwaliteit,
'' AS oppervlak,
'' AS attest,
'' AS afschuin_id,
inh_pr.opmerking AS opmerking
FROM 3_product_folder AS fld
LEFT JOIN 0_calculatie_inh_id_geg_product AS inh_pr
ON inh_pr.calculatie_inh_id = fld.product_id
LEFT JOIN 0_calculatie_inh_id AS id
ON id.id = inh_pr.calculatie_inh_id
LEFT JOIN 0_calculatie_id AS calc
ON calc.id = id.calculatie_id
WHERE fld.folder_id = '".$row_b['folder_id']."' AND id.soort = 'product'
ORDER BY inh_pr.naam ASC)
UNION ALL
(SELECT
fld.product_id AS product_id,
IF(id_plt.naam_in_pos = 'ja', CONCAT(srt.omschrijving,' ',calc.naam, ' ',inh_plt.pos), CONCAT(srt.omschrijving,' ',inh_plt.pos)) AS productnaam,
fld.aantal AS aantal,
CONCAT(inh_plt.lengte,'x',inh_plt.breedte,'x',inh_plt.dikte) AS afmeting,
inh_plt.proces AS proces,
fld.aantal * inh_plt.gewicht_stk AS gewicht,
kwal.kwaliteit AS kwaliteit,
opp.omschrijving AS oppervlak,
IF(inh_plt.attest > 0, inh_plt.attest, id_plt.attest_std) AS attest,
inh_plt.afschuin_id AS afschuin_id,
inh_plt.opmerking AS opmerking
FROM 3_product_folder AS fld
LEFT JOIN 0_calculatie_inh_id AS id
ON id.id = fld.product_id
LEFT JOIN 0_calculatie_id AS calc
ON calc.id = id.calculatie_id
LEFT JOIN 0_calculatie_id_geg_plaat AS id_plt
ON id_plt.calculatie_id_id = id.calculatie_id
LEFT JOIN 0_calculatie_inh_id_geg_plaat AS inh_plt
ON inh_plt.calculatie_inh_id = id.id
LEFT JOIN calculatie_omtrek AS srt
ON srt.id = inh_plt.soort_id
LEFT JOIN kwaliteit AS kwal
ON kwal.id = IF(inh_plt.kwaliteit_id > 0, inh_plt.kwaliteit_id, id_plt.kwaliteit_id_std)
LEFT JOIN kwaliteit_opp AS opp
ON opp.id = IF(inh_plt.oppervlak_id > 0, inh_plt.oppervlak_id, id_plt.oppervl_id_std)
WHERE fld.folder_id = '".$row_b['folder_id']."' AND id.soort = 'plaat'
ORDER BY inh_plt.dikte ASC)
";
但是查询没有在H_plt.dikte ASC中排序
当搜索这个网站和谷歌似乎是一个子查询无法订购?
但这是一个解决办法
我是不是误解了什么?请给我一些建议
按照Steve T的建议进行查询,结果为6/5/10
这两个查询都会对结果进行排序,但当您合并它们时,它们不会按照您期望的顺序显示。您可以添加一个envolving select查询,其中包含两个现有查询,然后按所需字段排序
编辑:
比如:
SELECT * FROM (
SELECT CustomerID as ID, CustomerName as Name FROM Customers
UNION ALL
SELECT EmployeeID as ID, LastName as Name FROM Employees
) a
ORDER BY a.ID;
这两个查询都会对结果进行排序,但当您合并它们时,它们不会按照您期望的顺序显示。您可以添加一个envolving select查询,其中包含两个现有查询,然后按所需字段排序
编辑:
比如:
SELECT * FROM (
SELECT CustomerID as ID, CustomerName as Name FROM Customers
UNION ALL
SELECT EmployeeID as ID, LastName as Name FROM Employees
) a
ORDER BY a.ID;
谢谢,我已经试过你的解决办法了。我得到了一个意想不到的结果。请参阅我编辑的文章。dikte
列必须是数字格式,才能按您的意愿工作。我猜您使用的是文本列,因此6
在10
字段dikte
设置为decimal(4,1)
后按字母顺序排列,但在第一个子查询中,您选择了dikte
作为“”,这使得它被作为字符串值覆盖谢谢,我已经尝试了您的解决方案。我得到了一个意想不到的结果。请参阅我编辑的文章。dikte
列必须是数字格式,才能按您的意愿工作。我猜您使用的是文本列,因此6
在10
字段dikte
设置为decimal(4,1)
后按字母顺序排列,但在第一个子查询中,您选择了dikte
作为“”,这使得它被作为字符串值覆盖