在MySQL中对SUM创建的总分进行排名

我有一个体操成绩表，其中只记录了单个器械的得分，所以我使用总和来创建一个总得分。显然，我可以对其进行排序，但我真的希望根据每个体操运动员的总得分值为“排名/位置”添加一个额外的列，而无需使用PHP进行进一步处理。我还想为每个单独的仪器设置一个“等级/位置！”：）

以下是我的“结果”表中的一些示例数据：

+---------+--------------+-------+
| gymnast | apparatus_id | score |
+---------+--------------+-------+
| Isla    |            1 | 12    |
| Isla    |            2 | 10.4  |
| Isla    |            3 | 11.5  |
| Bethany |            1 | 11.5  |
| Bethany |            2 | 10    |
| Bethany |            3 | 11    |
| Anna    |            1 | 12    |
| Anna    |            2 | 13    |
| Anna    |            3 | 10.25 |
+---------+--------------+-------+

然后我有一个类似下面的MySQL查询，将每个体操运动员的个人器械结果合并到一个列中，并创建总分数：

SELECT r.gymnast, app1.score AS app1_score, app2.score AS app2_score, app3.score AS app3_score, ROUND(app1.score+app2.score+app3.score, 2) AS overall_score
FROM (results r)
JOIN apparatuses a ON a.id = r.apparatus_id
LEFT JOIN results app1 ON app1.gymnast_id = r.gymnast_id AND app1.apparatus_id=1
LEFT JOIN results app2 ON app2.gymnast_id = r.gymnast_id AND app2.apparatus_id=2
LEFT JOIN results app3 ON app3.gymnast_id = r.gymnast_id AND app3.apparatus_id=3
GROUP BY r.gymnast
ORDER BY overall_score desc

所以现在我陷入了困境，我如何在这个查询的基础上为每个设备和整体添加一个等级/位置

+---------+------------+----------+------------+----------+------------+----------+---------------+-------------+
| gymnast | app1_score | app1_pos | app2_score | app2_pos | app3_score | app3_pos | overall_score | overall_pos |
+---------+------------+----------+------------+----------+------------+----------+---------------+-------------+
| Isla    | 12         | 1        | 10.4       | 2        | 11.5       | 1        | 33.9          | 2           |
| Bethany | 11.5       | 2        | 10         | 3        | 11         | 2        | 32.5          | 3           |
| Anna    | 12         | 1        | 13         | 1        | 10.25      | 3        | 35.25         | 1           |
+---------+------------+----------+------------+----------+------------+----------+---------------+-------------+

如果有人想玩，这里有一个SQL摆弄一些示例数据（）

编辑：有用的位

CREATE TABLE `apparatuses` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`id`),
  UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO `apparatuses` (`id`, `name`)
VALUES
(2,'Bars'),
(3,'Beam'),
(4,'Floor'),
(5,'Range & Conditioning'),
(1,'Vault');


CREATE TABLE `gymnasts` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`id`),
  UNIQUE KEY `name` (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO `gymnasts` (`id`, `name`)
VALUES
(21,'Abigail English'),
(73,'Alice Brunn'),
(40,'Amelia Hornik'),
(29,'Amelie Morgan'),
(53,'Anabelle Johnny'),
(36,'Anais Saunders '),
(2,'Anna Browne'),
(56,'Anna Walters'),
(33,'Annabelle Pinhorne'),
(54,'Aurora-Leigh Howard'),
(4,'Bethany Austin'),
(79,'Betty Macland'),
(37,'Bobbie Hardy'),
(6,'Bryony-Jasmine Ludlow'),
(48,'Caitlin Donaghy'),
(23,'Charlotte Anderson-Priddle'),
(63,'Chloe Holt'),
(34,'Chloe Ramse'),
(43,'Daisy Ellis'),
(35,'Dolcie Hansler'),
(26,'Elisha Stott'),
(76,'Ella Mead'),
(78,'Ellie Kis'),
(27,'Ellie-Mae Peach'),
(67,'Emily Rodrigo'),
(69,'Emily Tait'),
(71,'Emma Violet Merchant'),
(57,'Eva Matthews'),
(41,'Florence Self'),
(16,'Freya Shirley'),
(86,'Georgia Davies'),
(77,'Georgia Dawes'),
(13,'Georgia Luff'),
(22,'Georgia Pickford'),
(14,'Hallie Parkes'),
(45,'Helen Drummie'),
(50,'Hermionie Jones'),
(60,'Holly Rider'),
(72,'Isabel Schofield'),
(1,'Isla Pitman'),
(58,'Jemima Gregory'),
(18,'Jessica Siertsema'),
(20,'Joanne Pande'),
(84,'Kathryn Brooks'),
(83,'Katie Rutherford'),
(75,'Katie Stokes'),
(59,'Kiera Bessant'),
(28,'Kiera-Lily Rumley'),
(10,'Leah Stinson'),
(68,'Lexi Grinstead'),
(46,'Lexia Mullins'),
(61,'Lili Rogers'),
(24,'Lili-Mae Snuggs'),
(82,'Lizzieanna Quigley'),
(65,'Lotie Absolom'),
(85,'Lucy Washbourn'),
(30,'Maisie Lloyd-Jones'),
(70,'Mia Fergusson'),
(25,'Mia Perryment'),
(49,'Mikah Grieg'),
(44,'Millie Kerr'),
(7,'Mya Thomas-Osbourne'),
(11,'Natalia Ivanov'),
(62,'Natalia Tennant'),
(80,'Natasha Granville'),
(87,'Nathan Pitman'),
(66,'Niamh Hilton'),
(17,'Paige Cardner'),
(39,'Pauline Gibbe'),
(19,'Phoebe Boyton'),
(51,'Phoebe Johnson'),
(38,'Pippa Nowers'),
(42,'Poppy McBride'),
(8,'Rebekah Taylor'),
(31,'Ruby Brewer'),
(52,'Ruby Savage'),
(5,'Sasha Poole'),
(9,'Scarlett Liggins'),
(74,'Shannon Laverty'),
(55,'Sienna Chantey-Jowell'),
(47,'Sienna Rutherford'),
(3,'Sophie Prior'),
(12,'Sydney Whittle'),
(81,'Vicki Johnson'),
(32,'Zara Ahddoud');


CREATE TABLE `results` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `gymnast_id` int(11) NOT NULL,
  `apparatus_id` int(11) NOT NULL,
  `score` decimal(4,2) NOT NULL,
  PRIMARY KEY (`id`),
  KEY `gymnast_id` (`gymnast_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

INSERT INTO `results` (`id`, `gymnast_id`, `apparatus_id`, `score`)
VALUES
(5,1,1,11.55),
(6,1,2,13.15),
(7,1,3,11.40),
(8,1,4,11.80),
(9,1,5,12.30),
(10,2,1,11.75),
(11,2,2,12.65),
(12,2,3,11.45),
(13,2,4,11.30),
(14,2,5,12.55),
(26,3,1,12.20),
(27,3,2,12.65),
(28,3,3,10.85),
(29,3,4,11.70),
(30,3,5,10.40),
(31,4,1,11.00),
(32,4,2,12.25),
(33,4,3,10.75),
(34,4,4,11.35),
(35,4,5,11.90),
(36,5,1,11.80),
(37,5,2,11.50),
(38,5,3,9.80),
(39,5,4,11.60),
(40,5,5,11.65),
(41,11,1,9.00),
(42,11,2,11.10),
(43,11,3,5.90),
(44,11,4,9.70),
(45,11,5,10.30),
(46,6,1,12.75),
(47,6,2,12.90),
(48,6,3,11.15),
(49,6,4,12.15),
(50,6,5,10.70),
(51,10,1,10.60),
(52,10,2,12.50),
(53,10,3,8.35),
(54,10,4,11.30),
(55,10,5,9.80),
(56,8,1,11.10),
(57,8,2,11.05),
(58,8,3,11.90),
(59,8,4,10.45),
(60,8,5,10.70),
(61,9,1,9.50),
(62,9,2,11.85),
(63,9,3,5.75),
(64,9,4,9.70),
(65,9,5,10.75),
(66,12,1,11.85),
(67,12,2,11.65),
(68,12,3,11.65),
(69,12,4,10.90),
(70,12,5,8.80),
(71,13,1,11.50),
(72,13,2,11.80),
(73,13,3,10.40),
(74,13,4,10.10),
(75,13,5,10.35),
(76,14,1,11.40),
(77,14,2,11.10),
(78,14,3,10.80),
(79,14,4,11.05),
(80,14,5,11.25),
(81,7,1,11.70),
(82,7,2,13.00),
(83,7,3,11.30),
(84,7,4,12.55),
(85,7,5,11.75),
(86,16,1,12.30),
(87,16,2,13.30),
(88,16,3,9.30),
(89,16,4,11.85),
(90,16,5,8.25),
(91,17,1,12.50),
(92,17,2,13.05),
(93,17,3,12.00),
(94,17,4,12.30),
(95,17,5,8.15),
(96,18,2,10.20),
(97,18,3,10.90),
(98,18,4,9.95),
(99,18,5,10.25),
(100,19,1,12.80),
(101,19,2,13.55),
(102,19,3,11.45),
(103,19,4,12.30),
(104,19,5,10.70),
(105,20,1,11.90),
(106,20,2,11.35),
(107,20,3,11.85),
(108,20,4,11.55),
(109,20,5,9.05),
(110,21,1,12.65),
(111,21,2,11.00),
(112,21,3,9.80),
(113,21,4,11.95),
(114,21,5,11.70),
(115,22,1,11.40),
(116,22,2,12.65),
(117,22,3,8.80),
(118,22,4,11.10),
(119,22,5,9.75),
(120,23,1,12.00),
(121,23,2,9.35),
(122,23,3,8.30),
(123,23,4,11.60),
(124,23,5,11.85),
(125,24,1,13.00),
(126,24,2,9.40),
(127,24,3,7.30),
(128,24,4,11.40),
(129,24,5,11.85),
(130,25,1,11.60),
(131,25,2,10.20),
(132,25,3,6.00),
(133,25,4,10.55),
(134,25,5,12.10),
(135,26,1,11.40),
(136,26,2,11.20),
(137,26,3,6.70),
(138,26,4,10.25),
(139,26,5,10.70),
(140,27,1,13.55),
(141,27,2,9.10),
(142,27,3,10.70),
(143,27,4,9.30),
(144,27,5,7.35),
(145,28,1,12.65),
(146,28,2,12.50),
(147,28,3,3.90),
(148,28,4,9.35),
(149,28,5,10.40),
(150,29,1,13.20),
(151,29,2,11.90),
(152,29,3,10.90),
(153,29,4,12.65),
(154,29,5,12.90),
(155,30,1,12.30),
(156,30,2,10.00),
(157,30,3,9.80),
(158,30,4,9.70),
(159,30,5,12.50),
(453,18,1,0.00);

---

下面的查询将为您提供排名正确的体操运动员id，然后您可以加入当前的查询

select gymnast_id,total_score, @curRank := @curRank + 1 AS rank
FROM      
(select gymnast_id,sum(score) as total_score from tablename group by gymnast_id)p, (SELECT @curRank := 0) r
ORDER BY  total_score desc;

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您可以显示您的示例输出吗？您的DB用户是否有权创建mysql视图或过程？如果您可以在sql FIDLE中加载您的数据，那么我可以为您构建完整的查询，我将添加注释来解释我的查询和逻辑