Mysql-其中最后一个X数字是确定值

我有一张这样的桌子：

清单： id、类型、日期

在MySQL中是否有方法返回最新order by date desc的计数，其中type='1'，但限制为3

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所以问题是，值类型为“1”的最后3项是否为“1”？

值类型为“1”的最后3项日期，日期顺序相反：

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类型1的最后3个日期，按日期顺序：

日期顺序相反的连续类型1项目数：

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表中最近3个条目中类型为1的项目计数

SELECT COUNT(*) FROM (
  SELECT type FROM mytable ORDER BY date DESC LIMIT 3
) as t1
WHERE t1.type = 1;

我想这就是你想要的

SELECT  *
FROM    (
        SELECT  *
        FROM    mytable
        WHERE   type = 1
        ORDER BY
                date DESC
        LIMIT 3
        ) q
ORDER BY
        date

SELECT  COUNT(*)
FROM    mytable
WHERE   (date, id) >
        (
        SELECT  date, id
        FROM    mytable
        WHERE   type <> 1
        ORDER BY
                date DESC
        LIMIT 1
        )

SELECT COUNT(*) FROM (
  SELECT type FROM mytable ORDER BY date DESC LIMIT 3
) as t1
WHERE t1.type = 1;