使用mysql的5分钟酒吧
我收集了如下格式的勾号数据使用mysql的5分钟酒吧,mysql,datetime,Mysql,Datetime,我收集了如下格式的勾号数据 "instrument","tick_time","ask","bid","askVol","bidVol" "EUR/USD","2011-07-24 20:00:01","1.43676","1.43666","1.13","4.13" "EUR/USD","2011-07-24 20:00:02","1.43676","1.43666","1.13","4.5" "EUR/USD","2011-07-24 20:00:03","1.43674","1.43664
"instrument","tick_time","ask","bid","askVol","bidVol"
"EUR/USD","2011-07-24 20:00:01","1.43676","1.43666","1.13","4.13"
"EUR/USD","2011-07-24 20:00:02","1.43676","1.43666","1.13","4.5"
"EUR/USD","2011-07-24 20:00:03","1.43674","1.43664","1.13","1.65"
"EUR/USD","2011-07-24 20:00:06","1.43675","1.43665","1.13","5.4"
"EUR/USD","2011-07-24 20:00:06","1.43677","1.43668","1.13","4.28"
"EUR/USD","2011-07-24 20:00:10","1.43676","1.43666","1.13","6.15"
"EUR/USD","2011-07-24 20:00:11","1.43679","1.43669","1.13","4.13"
现在我正在尝试用它来创建5分钟的酒吧。我尝试了以下sql
select ROUND(tick_time / (60*5)) * 60 * 5 as bar_time,
max(bid) as high,
min(bid) as low
from ticks
group by bar_time
我得到以下数据
"bar_time","high","low"
"20110724199900","1.43669","1.43661"
"20110724200200","1.4366","1.4358"
"20110724200500","1.43625","1.43579"
"20110724200800","1.4365","1.43608"
"20110724201100","1.43645","1.43601"
"20110724201400","1.43624","1.43573"
"20110724201700","1.43619","1.43591"
"20110724202000","1.43644","1.4359"
我该如何做以下工作
1-以日期时间格式格式化条形图时间: 假设您的是
%Y%m%d%H%i%s
,您可以使用mysql函数:
select str_to_date((ROUND(tick_time / (60*5)) * 60 * 5) , '%Y%m%d%H%i%s') as bar_time,
max(bid) as high,
min(bid) as low
from ticks
group by bar_time
您可能需要将函数的第一个参数(即,ROUND(…)
)转换为字符串。
另外,示例中的第一行包含时间“20110724199900”,您确定这99分钟吗
2-我不明白,你能解释一下你的意思吗?1-用datetime格式设置酒吧时间: 假设您的是
%Y%m%d%H%i%s
,您可以使用mysql函数:
select str_to_date((ROUND(tick_time / (60*5)) * 60 * 5) , '%Y%m%d%H%i%s') as bar_time,
max(bid) as high,
min(bid) as low
from ticks
group by bar_time
您可能需要将函数的第一个参数(即,ROUND(…)
)转换为字符串。
另外,示例中的第一行包含时间“20110724199900”,您确定这99分钟吗
2-不明白,你能解释一下你的意思吗?其他解决方案:
select
date_format(
date_sub(
tick_time,
INTERVAL (extract(MINUTE from tick_time) % 5) MINUTE
),
"%m-%d%Y %H:%i"
) as bar_time,
MAX(bid) AS high,
MIN(bid) AS low
from ticks
group by bar_time
其他解决方案:
select
date_format(
date_sub(
tick_time,
INTERVAL (extract(MINUTE from tick_time) % 5) MINUTE
),
"%m-%d%Y %H:%i"
) as bar_time,
MAX(bid) AS high,
MIN(bid) AS low
from ticks
group by bar_time
我得到/*SQL错误(1054):“字段列表”中的未知列“ler_ts”*/已更正-需要勾选才能听到。也请投票/接受你喜欢的答案。我得到/*SQL错误(1054):“字段列表”中的未知列“ler\u ts”*/更正-需要勾选才能听到。也请投票/接受你喜欢的答案。另一个可能的重复,可能更好,等价物:我想获得分组的第一次出价和分组的最后一次出价另一个可能更好的重复,等价物:我想获得分组的第一次投标和分组的最后一次投标。我想获得分组的第一次投标和分组的最后一次投标。我想获得分组的第一次投标和分组的最后一次投标