Mysql 如何获取不使用'；t基于两个不同的表存在

我有以下表格设置：

//客户

+-----------+----------+------------+
| Id        | Client   | Status     |
+-----------+----------+------------+
| 1         | A        | Active     |
| 2         | B        | Active     |
| 3         | C        | Inactive   |
+-----------+----------+------------+

//经理台

+-----------+----------+
| clientId  | managerId|
+-----------+----------+
| 1         | 1        |
| 2         | 2        |
| 3         | 3        |
+-----------+----------+

//用户表

+-----------+----------+
| id        | firstName|
+-----------+----------+
| 1         | Carrera  |
| 2         | Taylor   |
| 3         | Diaz     |
+-----------+----------+

//期望输出

+-----------+----------+
| clientId  | managerId|
+-----------+----------+
| 1         | 2        |
| 1         | 3        |
| 2         | 1        |
| 2         | 3        |
+-----------+----------+

如何编写查询以获得所需的输出？我尝试过类似的方法，但结果并不理想：

select c.id as "Client"
     , u.id as "user" 
  from managers cm 
  left 
  join users u 
    on u.id = cm.managerId 
  left 
  join clients c 
    on c.id = cm.clientId 
 where cm.managerId not in (select id from users where firstName like '%a%') 
   and cm.clientId not in (select id from clients where status = 'Active');

---

有趣的想法是

WHERE

子句，因为您需要活动客户机并排除表管理器中的现有连接

客户ID | ManagerId -------: | --------: 1 | 2 1 | 3 2 | 1 2 | 3 小提琴

CREATE TABLE managers (
  `clientId` INTEGER,
  `managerId` INTEGER
);

INSERT INTO managers
  (`clientId`, `managerId`)
VALUES
  ('1', '1'),
  ('2', '2'),
  ('3', '3');

CREATE TABLE Clients (
  `Id` INTEGER,
  `Client` VARCHAR(1),
  `Status` VARCHAR(8)
);

INSERT INTO Clients
  (`Id`, `Client`, `Status`)
VALUES
  ('1', 'A', 'Active'),
  ('2', 'B', 'Active'),
  ('3', 'C', 'Inactive');

CREATE TABLE users (
  `id` INTEGER,
  `firstName` VARCHAR(7)
);

INSERT INTO users
  (`id`, `firstName`)
VALUES
  ('1', 'Carrera'),
  ('2', 'Taylor'),
  ('3', 'Diaz');

SELECT c.`Id` as ClientId ,u.id as ManagerId  FROM users u CROSS JOIN Clients c
WHERE c.`Status` = 'Active' AND (u.id,c.`Id`) NOT IN (SELECT `clientId`, `managerId` FROM managers)
ORDER By ClientId,ManagerId

ClientId | ManagerId -------: | --------: 1 | 2 1 | 3 2 | 1 2 | 3