Mysql 如何从数据库中获取唯一记录？

这是我的桌子结构

album
id ---- albumname
1   General
3   Sports
9   Activities
gallery
id --- ablumid--- image_thumb  --              image_full
1   1   uploads/1358401616.jpg  uploads/thumbs/thumb_1358401616.jpg
2   1   uploads/1358401641.jpg  uploads/thumbs/thumb_1358401641.jpg
3   1   uploads/1358402071.jpg  uploads/thumbs/thumb_1358402071.jpg
4   3   uploads/1358402334.jpg  uploads/thumbs/thumb_1358402334.jpg

问题是我有太多的图片，一个单一的画廊

这是我的mysql查询

SELECT DISTINCT gl.catid as gallery_cat_id, ab.albumname,gl.imagest 
FROM albums as ab 
INNER JOIN gallery as gl  ON ab.id=gl.catid 
order by ab.albumname ASC

结果如下

gallery_id  albumname   image_full
38      Activities       uploads/thumbs/thumb_1358424428.jpg
41      Activities       uploads/thumbs/thumb_1358424483.jpg
40      Activities       uploads/thumbs/thumb_1358424468.jpg
39      Activities       uploads/thumbs/thumb_1358424446.jpg

查询显示了我在查询中添加的库表中的所有记录，但它不起作用。

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有人能告诉我这里遗漏了什么吗？

如果每个相册只需要一个图像（无论是什么），可以使用GROUP BY子句，按相册id分组：

SELECT gl.catid as gallery_cat_id, ab.albumname, gl.imagest 
FROM
  albums as ab 
  INNER JOIN gallery as gl
  ON ab.id=gl.catid 
GROUP BY ab.id
order by ab.albumname ASC

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这看起来像是四个独特的行来解释你需要什么。独特的相册名称？查询的预期结果是什么？我需要显示相册。实际上我有三张专辑。我需要显示3个相册内的单一图像相册