Mysql 查找前两列的总和以及它们的点数？

正在尝试使用sum函数查找前2列

列可以是0或1整数值

表中所示为：

ID  C_ONE C_TWO C_THREE
1     1     1     0
2     0     1     1
3     1     1     0
4     0     0     0
5     1     1     0

CU DOWN列有4个点，CU ONE列有3个点，分别是前两列及其值

我已经被这个密码绊倒了

SELECT COUNT(ID)
FROM MY_TABLE
ORDER BY SUM(C_ONE), SUM(C_TWO), SUM(C_THREE)
LIMIT 2

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那么，您可以取消PIVOT并聚合：

select c.col,
       (case when c.col = 'col1' then t.col1
             when c.col = 'col2' then t.col2
             when c.col = 'col3' then t.col3
        end) as cnt
from (select sum(col1) as col1, sum(col2) as col2, sum(col3) as col3
      from t
     ) t cross join
     (select 'col1' as col union all
      select 'col2' as col union all
      select 'col3' as col
     ) c
order by cnt desc
limit 2;

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昨天有人问了一个非常类似的问题。那不是什么人。。那是同样的一个熟悉的，tho！