Mysql 如何通过一列组合两个不同的查询结果

Mysql 如何通过一列组合两个不同的查询结果,mysql,sql,Mysql,Sql,我试图通过在两个查询中返回相等值的字段锚来合并两个查询的结果 SELECT anchor_date AS anchor, <======================= query one, field "anchor" SUM( GETVAL(24, entry_id) ) AS valueQ1 <======= query one, field "valueQ1" FROM users WHERE blog_id = 173 GROUP BY DATE(

我试图通过在两个查询中返回相等值的字段锚来合并两个查询的结果

 SELECT
    anchor_date AS anchor, <======================= query one, field "anchor"
    SUM( GETVAL(24, entry_id) ) AS valueQ1 <======= query one, field "valueQ1"
 FROM users
 WHERE blog_id = 173
 GROUP BY DATE(anchor)

 UNION

 SELECT
    anchor AS anchor, <============================ query two, field "anchor"
    SUM(value) AS valueQ2 <======================== query two, field "valueQ2"
 FROM infodata
 WHERE infoid IN(330, 1492, 1066)
 AND entity = 173

我尝试使用联合,但没有成功。也许是交集还是加入?

我正要修正我的答案,然后我看到了你的答案+1不确定,但你都试过了吗?
SELECT anchor, MAX(valueQ1) AS valueQ1, MAX(valueQ2) AS valueQ2
FROM (
    SELECT
        anchor_date AS anchor,
        SUM( GETVAL(24, entry_id) ) AS valueQ1,
        NULL AS valueQ2
     FROM users
     WHERE blog_id = 173
     GROUP BY DATE(anchor)

     UNION

     SELECT
        anchor AS anchor,
        NULL AS valueQ1,
        SUM(value) AS valueQ2
     FROM infodata
     WHERE infoid IN(330, 1492, 1066)
     AND entity = 173) AS u
GROUP BY anchor
SELECT anchor, MAX(valueQ1) AS valueQ1, MAX(valueQ2) AS valueQ2
FROM (
    SELECT
        anchor_date AS anchor,
        SUM( GETVAL(24, entry_id) ) AS valueQ1,
        NULL AS valueQ2
     FROM users
     WHERE blog_id = 173
     GROUP BY DATE(anchor)

     UNION

     SELECT
        anchor AS anchor,
        NULL AS valueQ1,
        SUM(value) AS valueQ2
     FROM infodata
     WHERE infoid IN(330, 1492, 1066)
     AND entity = 173) AS u
GROUP BY anchor