Mysql从发票中减去付款
我已经找过了,但没有找到适合我的东西。我有三张桌子。一个是客户Id名称查找、付款表和invloice表。每个客户都有一个或多个发票记录,其中包含欠款。客户在付款表中有0条或多条记录。付款可能针对多张发票,也可能针对一张发票进行多次付款。我想得到每个客户的欠款总额。例如,增加每个客户的所有发票,减去每个客户的所有付款Mysql从发票中减去付款,mysql,Mysql,我已经找过了,但没有找到适合我的东西。我有三张桌子。一个是客户Id名称查找、付款表和invloice表。每个客户都有一个或多个发票记录,其中包含欠款。客户在付款表中有0条或多条记录。付款可能针对多张发票,也可能针对一张发票进行多次付款。我想得到每个客户的欠款总额。例如,增加每个客户的所有发票,减去每个客户的所有付款 Invoices Payments Clients -------------------- ----------
Invoices Payments Clients
-------------------- ------------------ -----------
|Id|ClientId|Amount| |Id|ClientId|Paid| |Id| Name |
|1 | 3 | 200 | | 1| 2 | 10 | | 1| Bob |
|2 | 2 | 10 | | 2| 1 | 20 | | 2| Tom |
|3 | 4 | 100 | | 3| 2 | 100| | 3| John |
|4 | 2 | 240 | | 4| 3 | 240| | 4| Peter |
| 5| 1 | 20 | ------------------ --------------
--------------------
Expected Result
----------------------
|Name |Spent|Paid|Total|
|John | 200 | 240| -40|
| Tom | 250 | 110| 140 |
|Peter| 100 | 0| 100 |
| Bob | 20 | 20| 0 |
------------------------
考虑以下几点:
DROP TABLE IF EXISTS invoices;
CREATE TABLE invoices
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,client_id INT NOT NULL
,amount DECIMAL(5,2) NOT NULL
);
INSERT INTO invoices VALUES
(1,3,200),
(2,2, 10),
(3,4,100),
(4,2,240),
(5,1, 20);
DROP TABLE IF EXISTS payments;
CREATE TABLE payments
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,client_id INT NOT NULL
,paid DECIMAL(5,2)
);
INSERT INTO payments VALUES
(1,2,10 ),
(2,1,20 ),
(3,2,100),
(4,3,240);
DROP TABLE IF EXISTS clients;
CREATE TABLE clients
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,name VARCHAR(12) NOT NULL
);
INSERT INTO clients VALUES
(1,'Bob'),
(2,'Tom'),
(3,'John'),
(4,'Peter');
SELECT c.name
, SUM(CASE WHEN x.type = 'invoice' THEN x.amount ELSE 0 END) spent
, SUM(CASE WHEN x.type = 'payment' THEN x.amount ELSE 0 END) paid
, SUM(CASE WHEN x.type = 'invoice' THEN x.amount ELSE x.amount * -1 END) total
FROM clients c
JOIN
( SELECT client_id
, 'invoice' type
, amount
FROM invoices
UNION
SELECT client_id
, 'payment'
, paid
FROM payments
) x
ON x.client_id = c.id
GROUP
BY c.id;
+-------+--------+--------+--------+
| name | spent | paid | total |
+-------+--------+--------+--------+
| Bob | 20.00 | 20.00 | 0.00 |
| Tom | 250.00 | 110.00 | 140.00 |
| John | 200.00 | 240.00 | -40.00 |
| Peter | 100.00 | 0.00 | 100.00 |
+-------+--------+--------+--------+
要了解其工作原理,请尝试仅执行子查询位SELECT client\u id。。。从付款中这是一个提示:按客户ID从发票组中选择sumamount作为“已用”,按客户ID从付款组中选择sumamount作为“已付”,依此类推当我在表上使用select时,结果不正确。一位客户有3条记录,总计7000美元的付款,3条记录,总计7000美元的发票,其结果为21000美元的发票和21000美元的付款。进行更改-仍然与更改前完全相同。感谢您的帮助。“付款”部分中缺少“类型”,这有一个小错误。我需要做什么才能得到非零的总数。我不认为这是一个“错误”!?!2.你可以做很多事情。最简单也是最慢的方法是在查询末尾添加HAVING子句。除了最慢的方法之外,还有什么建议吗?