mysql:基于json的查询
代码:mysql:基于json的查询,mysql,json,Mysql,Json,代码: CREATE TABLE t1(jdoc JSON); INSERT INTO t1 VALUES('{ "data": [ { "type": "required", "member": { "id" : "1001", "response": "none" }
CREATE TABLE t1(jdoc JSON);
INSERT INTO t1 VALUES('{
"data":
[
{
"type": "required",
"member": {
"id" : "1001",
"response": "none"
}
},
{
"type": "notrequired",
"member": {
"id" : "1009",
"response": "accepted"
}
}
]
}');
INSERT INTO t1 VALUES('{
"data":
[
{
"type": "maybe",
"member": {
"id" : "1002",
"response": "none"
}
},
{
"type": "maybe",
"member": {
"id" : "1003",
"response": "accepted"
}
}
]
}');
我有两个问题
SELECT * FROM t1 where JSON_CONTAINS(jdoc, JSON_QUOTE('1002'), '$.data[*].memeber.id');
SELECT * FROM t1 where JSON_EXTRACT(jdoc, '$.data[*].memeber.id') = '1002';
请帮助我查询。您的查询中有输入错误:memeber@IgorVujovic是的,没错。。它应该是“成员”