Mysql 从表中选择并更新另一个表SQL
我正在尝试从“reviews”表中获取“business\u id”和“rating”,其中“review\u id”是$ApproveView 然后使用从“评论”中检索到的评级更新“业务详细信息”中的“评级”,其中“业务id”等于检索到的评级 我有两个疑问,Mysql 从表中选择并更新另一个表SQL,mysql,sql,sql-update,Mysql,Sql,Sql Update,我正在尝试从“reviews”表中获取“business\u id”和“rating”,其中“review\u id”是$ApproveView 然后使用从“评论”中检索到的评级更新“业务详细信息”中的“评级”,其中“业务id”等于检索到的评级 我有两个疑问, SELECT business_id, rating FROM reviews WHERE review_id = '$approveReviewID'; UPDATE business_details SET rating = rat
SELECT business_id, rating FROM reviews WHERE review_id = '$approveReviewID';
UPDATE business_details SET rating = rating + $rating WHERE business_id = '$businessID';
有没有办法将这些查询合并为一个查询?是的,您可以使用update join语法:
UPDATE business_details bd
JOIN reviews r ON bd.business_id = r.business_id
SET bd.rating = bd.rating + r.rating
WHERE r.review_id = '$approveReviewID'
在from子句中使用简单的“内部联接”联接两个表
UPDATE bd
SET rating = bd.rating + rvs.rating
FROM reviews rvs
INNER JOIN business_details bd ON db.business_id = rvs.business_id
WHERE rvs.review_id = '$approveReviewID'