Mysql 带SUM的左联接未返回正确的值

我有一张有各种成本明细的发票表。 我有一个链接表与杂项成本以及。 关系是一张发票与许多杂项成本的关系

当我执行SUM（）时，如果杂项成本表（右）上存在多行，则发票表（左）中的值将乘以找到的行数

DB小提琴：

劳动力、零件、POL和次级分包的原始查询结果不正确：

SELECT  SUM(ad.labour_cost) AS LABOUR,
    SUM(ad.part_cost) AS PARTS,
    SUM(ad.pol_cost) AS POLS,
    SUM(ad.sublet_cost) AS SUBLET,
    SUM(am.misc_sales_amt)  AS MISC
FROM AdvisorSalesData ad 
LEFT JOIN AdvisorMiscSalesData am 
  ON (ad.customer_id=am.customer_id AND ad.invoice_no=am.invoice_no)
WHERE ad.customer_id IN (3)

调整的查询-删除了内部联接，并尝试对misc表进行单个选择，但misc的结果不正确（NULL）：

如何调整以在一个查询中获得所有5列的正确结果？

加入前聚合：

他是一把小提琴

可以在子查询中重复筛选以获得更好的性能：

SELECT SUM(ad.labour) AS LABOUR,
       SUM(ad.parts) AS PARTS,
       SUM(ad.pols) AS POLS,
       SUM(ad.sublet) AS SUBLET,
       SUM(am.misc)  AS MISC
FROM (SELECT customer_id, invoice_no,
             SUM(ad.labour_cost) AS LABOUR,
             SUM(ad.part_cost) AS PARTS,
             SUM(ad.pol_cost) AS POLS,
             SUM(ad.sublet_cost) as sublet
      FROM AdvisorSalesData ad 
      WHERE ad.customer_id IN (3)
      GROUP BY customer_id, invoice_no
     ) ad LEFT JOIN
     (SELECT customer_id, invoice_no,
             SUM(am.misc_sales_amt) AS MISC
      FROM AdvisorMiscSalesData am 
      WHERE ad.customer_id IN (3)
      GROUP BY customer_id, invoice_no
     ) am
     ON ad.customer_id = am.customer_id AND    
        ad.invoice_no = am.invoice_no
WHERE ad.customer_id IN (3);

---

一对多还是多对多？预期的结果是什么？戈登，正确的小提琴：完成后你必须点击更新，否则你只是在复制旧的。干杯。返回正确的结果-谢谢。。。但是，当我把它重新添加到代码中时，执行起来需要269秒。。。。

SELECT SUM(ad.labour) AS LABOUR,
       SUM(ad.parts) AS PARTS,
       SUM(ad.pols) AS POLS,
       SUM(ad.sublet) AS SUBLET,
       SUM(am.misc)  AS MISC
FROM (SELECT customer_id, invoice_no,
             SUM(ad.labour_cost) AS LABOUR,
             SUM(ad.part_cost) AS PARTS,
             SUM(ad.pol_cost) AS POLS,
             SUM(ad.sublet_cost) as sublet
      FROM AdvisorSalesData ad 
      GROUP BY customer_id, invoice_no
     ) ad LEFT JOIN
     (SELECT customer_id, invoice_no,
             SUM(am.misc_sales_amt) AS MISC
      FROM AdvisorMiscSalesData am 
      GROUP BY customer_id, invoice_no
     ) am
     ON ad.customer_id = am.customer_id AND    
        ad.invoice_no = am.invoice_no
WHERE ad.customer_id IN (3);

SELECT SUM(ad.labour) AS LABOUR,
       SUM(ad.parts) AS PARTS,
       SUM(ad.pols) AS POLS,
       SUM(ad.sublet) AS SUBLET,
       SUM(am.misc)  AS MISC
FROM (SELECT customer_id, invoice_no,
             SUM(ad.labour_cost) AS LABOUR,
             SUM(ad.part_cost) AS PARTS,
             SUM(ad.pol_cost) AS POLS,
             SUM(ad.sublet_cost) as sublet
      FROM AdvisorSalesData ad 
      WHERE ad.customer_id IN (3)
      GROUP BY customer_id, invoice_no
     ) ad LEFT JOIN
     (SELECT customer_id, invoice_no,
             SUM(am.misc_sales_amt) AS MISC
      FROM AdvisorMiscSalesData am 
      WHERE ad.customer_id IN (3)
      GROUP BY customer_id, invoice_no
     ) am
     ON ad.customer_id = am.customer_id AND    
        ad.invoice_no = am.invoice_no
WHERE ad.customer_id IN (3);