MySQL查询中的查询语法错误

这是我的疑问：

SELECT
   `i`.`itemtype` AS `Item`,
   `p`.`name`
   (SELECT SUM(`i`.`count`) AS `Count` WHERE `itemtype` = 2148),
   (SELECT SUM(`i`.`count`) * 100 AS `Count1` WHERE `itemtype` = 2152),
   (SELECT SUM(`i`.`count`) * 10000 AS `Count2` WHERE `itemtype` = 2160)
FROM `player_items` AS `i`
LEFT JOIN `players` AS `p` ON (`p`.`id` = `i`.`player_id`)
WHERE `i`.`itemtype` IN (2148, 2152, 2160)
GROUP BY `i`.`itemtype`
LIMIT 0, 30

当我在mysql中运行上述查询时，我得到以下错误消息：

#1064 - You have an error in your SQL syntax; check the manual that corresponds
to your MySQL server version for the right syntax to use near
'SELECT SUM(`i`.`count`) AS `Count` WHERE `itemtype` = 2148)
   , (SELECT SUM(`i`' at line 4

我完全不明白这意味着什么，因为我是MySQL中的乞丐。

在你所有的选择中。。。在所有选择的总和中，您没有将FROM player_项目定义为i

。。。您没有将FROM player_项目定义为i故障：-

SELECT SUM(`i`.`count`) AS `Count` <-- missing FROM which table

故障：-

SELECT SUM(`i`.`count`) AS `Count` <-- missing FROM which table

---

此列后缺少逗号：

`p`.`name`

请考虑以下查询：

SELECT i.itemtype AS Item
   , p.name
   , SUM(CASE 
            WHEN itemtype = 2148 THEN i.count
            ELSE 0
         END) AS Count
   , SUM(CASE
            WHEN itemtype = 2152 THEN i.count
            ELSE 0
         END) * 100 AS Count1
   , SUM(CASE
            WHEN itemtype = 2160 THEN i.count
            ELSE 0
         END) * 10000 AS Count2
FROM player_items AS i
LEFT JOIN players AS p ON i.player_id = p.id
WHERE i.itemtype IN (2148, 2152, 2160)
GROUP BY i.itemtype ASC
LIMIT 0, 30

要将这三列相加，您可以：

SELECT t.itemType AS Item, t.Count, t.Count1, t.Count2
   , SUM(t.Count1, t.Count2, t.Count3) AS Total
FROM
(
   SELECT i.itemtype AS Item
      , p.name
      , SUM(CASE 
               WHEN itemtype = 2148 THEN i.count
               ELSE 0
            END) AS Count
      , SUM(CASE
               WHEN itemtype = 2152 THEN i.count
               ELSE 0
            END) * 100 AS Count1
      , SUM(CASE
               WHEN itemtype = 2160 THEN i.count
               ELSE 0
            END) * 10000 AS Count2
   FROM player_items AS i
   LEFT JOIN players AS p ON i.player_id = p.id
   WHERE i.itemtype IN (2148, 2152, 2160)
   GROUP BY i.itemtype ASC
   LIMIT 0, 30
) AS t

或者你可以再加一个例子

---

这使得您无需运行另外三条SELECT语句来返回相同的结果。

此列后缺少逗号：

`p`.`name`

请考虑以下查询：

SELECT i.itemtype AS Item
   , p.name
   , SUM(CASE 
            WHEN itemtype = 2148 THEN i.count
            ELSE 0
         END) AS Count
   , SUM(CASE
            WHEN itemtype = 2152 THEN i.count
            ELSE 0
         END) * 100 AS Count1
   , SUM(CASE
            WHEN itemtype = 2160 THEN i.count
            ELSE 0
         END) * 10000 AS Count2
FROM player_items AS i
LEFT JOIN players AS p ON i.player_id = p.id
WHERE i.itemtype IN (2148, 2152, 2160)
GROUP BY i.itemtype ASC
LIMIT 0, 30

要将这三列相加，您可以：

SELECT t.itemType AS Item, t.Count, t.Count1, t.Count2
   , SUM(t.Count1, t.Count2, t.Count3) AS Total
FROM
(
   SELECT i.itemtype AS Item
      , p.name
      , SUM(CASE 
               WHEN itemtype = 2148 THEN i.count
               ELSE 0
            END) AS Count
      , SUM(CASE
               WHEN itemtype = 2152 THEN i.count
               ELSE 0
            END) * 100 AS Count1
      , SUM(CASE
               WHEN itemtype = 2160 THEN i.count
               ELSE 0
            END) * 10000 AS Count2
   FROM player_items AS i
   LEFT JOIN players AS p ON i.player_id = p.id
   WHERE i.itemtype IN (2148, 2152, 2160)
   GROUP BY i.itemtype ASC
   LIMIT 0, 30
) AS t

或者你可以再加一个例子

---

这使得您无需运行另外三条SELECT语句来返回相同的结果。

我想您需要这样的结果：

SELECT p.name
      ,i.itemtype
      ,CASE itemtype 
         WHEN 2148 THEN count(*)
         WHEN 2152 THEN count(*) * 100
         WHEN 2160 THEN count(*) * 10000
       END AS ct
FROM   players p
LEFT   JOIN player_items i ON p.id = i.player_id
WHERE  i.itemtype IN (2148, 2152, 2160)
GROUP  BY p.name, i.itemtype
ORDER  BY p.name, i.itemtype
LIMIT  30;

或者，也许是这样：

SELECT p.name
      ,sum(CASE WHEN itemtype = 2148 THEN 1 ELSE 0 END) AS ct
      ,sum(CASE WHEN itemtype = 2152 THEN 1 ELSE 0 END) * 100 AS ct1
      ,sum(CASE WHEN itemtype = 2160 THEN 1 ELSE 0 END) * 10000 AS ct2
FROM   players p
LEFT   JOIN player_items i ON p.id = i.player_id
WHERE  i.itemtype IN (2148, 2152, 2160)
GROUP  BY p.name
ORDER  BY p.name
LIMIT  30;

---

请看。

我想您想要这样的东西：

SELECT p.name
      ,i.itemtype
      ,CASE itemtype 
         WHEN 2148 THEN count(*)
         WHEN 2152 THEN count(*) * 100
         WHEN 2160 THEN count(*) * 10000
       END AS ct
FROM   players p
LEFT   JOIN player_items i ON p.id = i.player_id
WHERE  i.itemtype IN (2148, 2152, 2160)
GROUP  BY p.name, i.itemtype
ORDER  BY p.name, i.itemtype
LIMIT  30;

或者，也许是这样：

SELECT p.name
      ,sum(CASE WHEN itemtype = 2148 THEN 1 ELSE 0 END) AS ct
      ,sum(CASE WHEN itemtype = 2152 THEN 1 ELSE 0 END) * 100 AS ct1
      ,sum(CASE WHEN itemtype = 2160 THEN 1 ELSE 0 END) * 10000 AS ct2
FROM   players p
LEFT   JOIN player_items i ON p.id = i.player_id
WHERE  i.itemtype IN (2148, 2152, 2160)
GROUP  BY p.name
ORDER  BY p.name
LIMIT  30;

---

请参阅。

感谢您提供了一个好的解决方案。顺便说一句。是否可以将另一行的Count、Count1和Count2相加？@Cyclone我已经更新了我的答案，以解决您评论中的问题。谢谢您提供了一个好的解决方案。顺便说一句，是否可以将另一行的Count、Count1和Count2相加？我已经更新了我的答案，以解决您评论中的问题。