Mysql 选择持续超过1秒的状态

我有一个问题看起来很简单，但我找不到解决办法

所以，我有一张桌子，上面有两个可乐，像这样：

Time Status 00:00:00.111 Off 00:00:00.222 On 00:00:00.345 On 00:00:01.555 On 00:00:01.666 Off 00:00:02.222 On 00:00:02.422 On 00:00:02.622 Off 00:00:05.888 Off 00:00:05.999 Off 时间状态 00:00:00.111关闭 00:00:00.222开 00:00:00.345开 00:00:01.555 On 00:00:01.666关闭 00:00:02.222开 00:00:02.422 On 00:00:02.622关 00:00:05.888关闭 00:00:05.999关闭 我想选择所有持续超过1秒的状态， 在本例中，我需要以下序列：

00:00:00.222 On 00:00:00.345 On 00:00:01.555 On 00:00:00.222开 00:00:00.345开 00:00:01.555 On

---

你们能给我一些线索吗？非常感谢

简单的

分组依据

和

总和

无法在当前数据集上执行此操作，因此我的想法是添加一个帮助器列：

CREATE TABLE someTable(
`time` DATETIME,
status CHAR(3),
helperCol INT
);

helperCol是一个INT，将按如下方式设置：

CREATE PROCEDURE setHelperCol() 
BEGIN
  DECLARE finished,v_helperCol INT;
  DECLARE status CHAR(3);
  DECLARE ts DATETIME;
  DECLARE CURSOR st FOR SELECT `time`,status,helperCol FROM someTable WHERE helperCol IS NOT NULL; -- Handy for re-use: No need to go over all data, so you can save the helperCol as permanent value.
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET finished = 1;
  SELECT @maxVal:=MAX(helperCol) FROM helperCol;

  SET finished=0;
  SET helperCol=@maxVal;
  IF(!helperCol>0) SET helperCol=1;
  OPEN st;
  FETCH ts,status,v_helperCol FROM st;
  WHILE(finished=0) DO
    IF(status='Off') v_helperCol=v_helperCol+1;
    UPDATE someTable SET helperCol=v_helperCol WHERE `time`=ts; -- Assuming `time` is unique;
    FETCH ts,status,v_helperCol FROM st;
  END WHILE;
  CLOSE st;
END;

执行该过程，结果是：

Time               Status  helperCol
00:00:00.111       Off      2
00:00:00.222       On       2
00:00:00.345       On       2
00:00:01.555       On       2
00:00:01.666       Off      3
00:00:02.222       On       3
00:00:02.422       On       3
00:00:02.622       Off      4

现在可以对其进行分组和处理：

SELECT MAX(`time`)-MIN(`time`) AS diffTime
FROM someTable
WHERE status='ON'
GROUP BY helperCol
HAVING MAX(`time`)-MIN(`time`)>1;

其结果是（您需要搜索要应用于

MAX-MIN

部分的正确

datetime

函数）：

备选方案：

---

您也可以在存储过程中处理

MAX-MIN

，但这不会像helperColumn解决方案那样有效地重复。

数据类型是什么？它是哪个版本的SQL/MySQL？我想这会有帮助：在你想要的前两个结果之间，不到一秒钟。为什么？谢谢你，Marekful。我的意思是On的状态从00:00.222持续到00:00:01.555，持续时间大于1秒。那么您的描述不准确。您希望选择第一行和最后一行之间经过的时间超过1秒并后跟“关闭”的所有连续“打开”状态行。这是正确的吗？是的，这正是我想要的，我会修改帖子，谢谢。嗨，诺伯特，非常感谢你的回答，解决方案看起来很好。然而，在我的情况下，我会有一个巨大的表，我需要选择所有这些状态持续超过一秒钟。我会进一步考虑这个问题，我通过使过程递增来考虑大表：当添加数据时，过程只需处理新零件。通过在

helperCol

上添加索引，速度会更快。

SELECT a.time start
     , MIN(c.time) end
     , TIMEDIFF(MIN(c.time),a.time) duration
  FROM 
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) a
  LEFT
  JOIN
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) b
    ON b.status = a.status
   AND b.rank = a.rank - 1
  JOIN
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) c
    ON c.rank >= a.rank
  LEFT 
  JOIN 
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) d
    ON d.status = c.status 
   AND d.rank = c.rank + 1
 WHERE b.rank IS NULL
   AND d.rank IS NULL
   AND a.status = 1
 GROUP
    BY a.time
HAVING duration >= 1;

SELECT a.time start
     , MIN(c.time) end
     , TIMEDIFF(MIN(c.time),a.time) duration
  FROM 
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) a
  LEFT
  JOIN
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) b
    ON b.status = a.status
   AND b.rank = a.rank - 1
  JOIN
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) c
    ON c.rank >= a.rank
  LEFT 
  JOIN 
     ( SELECT x.*,  COUNT(*) rank FROM my_table x JOIN my_table y ON y.time <= x.time GROUP BY time ) d
    ON d.status = c.status 
   AND d.rank = c.rank + 1
 WHERE b.rank IS NULL
   AND d.rank IS NULL
   AND a.status = 1
 GROUP
    BY a.time
HAVING duration >= 1;

SELECT time
     , status 
     , cumulative
  FROM 
     ( SELECT *
            , CASE WHEN @prev = status THEN @i:=@i+duration ELSE @i:=0 END cumulative
            , @prev:=status
         FROM 
            ( SELECT x.*
                   , TIME_TO_SEC(MIN(y.time))-TIME_TO_SEC(x.time) duration 
                FROM my_table x 
                JOIN my_table y 
                  ON y.time > x.time 
               GROUP 
                  BY x.time
            ) n
        ORDER 
           BY time
     ) a
 WHERE cumulative >= 1
   AND status = 1;