Mysql 更新具有其他列的一个或多个相同值的列值

我有以下声明：

UPDATE `tblAllocatedLeads` 
SET tblAllocatedLeads.fldAllocatedStatus = CASE 
WHEN tblAllocatedLeads.fldAllocatedStatus = 'Allocated' 
AND 
(SELECT COUNT(*) FROM (SELECT * FROM `tblAllocatedLeads`) AS tblallocate WHERE AND tblallocate.fldAllocatedLeadId = tblAllocatedLeads.fldAllocatedLeadId) > 1 
THEN 'Outstanding' 
END

我想要的是将fldAllocatedStatus='Allocated'的所有行更新为'unquired'，该行具有一个或多个相同的fldAllocatedLeadId列值，并将其添加到其他行

我的数据

ID   fldAllocatedStatus   fldAllocatedLeadId
1    Accepted             123
2    Rejected             123
3    Allocated            123
4    Allocated            321

在这种情况下，ID=3应将fldAllocatedStatus更新为“未完成”，因为它从ID=1,2有一个或多个相同的fldAllocatedLeadId

ID=4应该保持“已分配”，因为它没有与其他行匹配的fldAllocatedLeadId

---

现在它所做的就是更新已接受的、已拒绝的数据，假定MySQL只更新已分配的行，我想您需要：

UPDATE tblAllocatedLeads al JOIN
       (SELECT al2.fldAllocatedLeadId
        FROM tblAllocatedLeads al2
        WHERE al.fldAllocatedStatus <> 'Allocated'
        GROUP BY al2.tblAllocatedLeads
       ) al2
       ON al2.tblAllocatedLeads = al.tblAllocatedLeads
    SET al.fldAllocatedStatus = 'Outstanding'
    WHERE al.fldAllocatedStatus = 'Allocated' ;

---

子查询获取具有未分配值的Lead。外部连接仅在有已分配行时更新该行。

您不需要任何聚合，只需要一个自连接：

UPDATE tblAllocatedLeads t 
INNER JOIN tblAllocatedLeads tt
ON tt.id <> t.id AND tt.fldAllocatedLeadId = t.fldAllocatedLeadId 
SET t.fldAllocatedStatus = 'Outstanding' 
WHERE t.fldAllocatedStatus = 'Allocated';

---

用你正在使用的数据库标记你的问题。与你的问题无关，但是：这一个工作得很好。非常感谢你！。我感谢你的帮助。

| ID  | fldAllocatedStatus | fldAllocatedLeadId |
| --- | ------------------ | ------------------ |
| 1   | Accepted           | 123                |
| 2   | Rejected           | 123                |
| 3   | Outstanding        | 123                |
| 4   | Allocated          | 321                |