MySQL查询，该查询将忽略重复次数最少且最多的结果

我需要一个MySQL查询来获得结果，其中不会有重复次数最多和最少的值

这意味着什么

如果此MySQL查询：

 SELECT Ocjena,COUNT(*) FROM ocjenjivanje GROUP BY Ocjena; 

返回：

我需要提供下一个结果的查询：

Ocjena 
1
3
5

谢谢

试试这个：

SELECT o.*
FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o
INNER JOIN (SELECT Min(c) AS l, Max(c) AS h FROM  (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena)) AS m
ON o.c <> m.l AND o.c <> m.h
----OR
--ON o.c NOT IN(m.l, m.h)

或者您可以使用此查询：

SELECT Ocjena, c
FROM
( SELECT o.*, @min:=IF(@min > o.c, o.c, @min) AS l, @max:=IF(@max < o.c, o.c, @max) AS h
  FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o
  , (select @max:=0, @min:=32000) AS m) AS x
WHERE c NOT IN(l, h)

SELECT o.*
FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o
INNER JOIN (SELECT Min(Ocjena) AS l, Max(Ocjena) AS h FROM ocjenjivanje) AS m
ON o.Ocjena <> m.l AND o.Ocjena <> m.h

SELECT Ocjena, COUNT(*) AS c 
FROM ocjenjivanje AS o
WHERE o.Ocjena <> (SELECT Min(Ocjena) FROM ocjenjivanje)
AND o.Ocjena <> (SELECT Max(Ocjena) FROM ocjenjivanje)
GROUP BY Ocjena

SELECT Ocjena, COUNT(*) AS c 
FROM ocjenjivanje AS o
WHERE o.Ocjena NOT IN (SELECT Min(Ocjena) FROM ocjenjivanje UNION SELECT Max(Ocjena) FROM ocjenjivanje)
GROUP BY Ocjena

这是我的解决办法

我不知道我能不能让自己看起来更专业或者更快，或者诸如此类

SELECT *    FROM     `Ocjenjivanje`  WHERE Ocjena != (    SELECT Ocjena 
FROM     `Ocjenjivanje`
GROUP BY `Ocjena`
ORDER BY `Ocjena` DESC
LIMIT 1) AND OCjena != ( SELECT Ocjena
FROM     `Ocjenjivanje`
GROUP BY `Ocjena`
ORDER BY `Ocjena` ASC
LIMIT 1)
GROUP BY `Ocjena`

---

您可以从答案中发布的查询中获得如下结果，但使用以下查询之一不会返回问题中所需的行：

SELECT Ocjena, c
FROM
( SELECT o.*, @min:=IF(@min > o.c, o.c, @min) AS l, @max:=IF(@max < o.c, o.c, @max) AS h
  FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o
  , (select @max:=0, @min:=32000) AS m) AS x
WHERE c NOT IN(l, h)

SELECT o.*
FROM (SELECT Ocjena, COUNT(*) AS c FROM ocjenjivanje GROUP BY Ocjena) AS o
INNER JOIN (SELECT Min(Ocjena) AS l, Max(Ocjena) AS h FROM ocjenjivanje) AS m
ON o.Ocjena <> m.l AND o.Ocjena <> m.h

SELECT Ocjena, COUNT(*) AS c 
FROM ocjenjivanje AS o
WHERE o.Ocjena <> (SELECT Min(Ocjena) FROM ocjenjivanje)
AND o.Ocjena <> (SELECT Max(Ocjena) FROM ocjenjivanje)
GROUP BY Ocjena

SELECT Ocjena, COUNT(*) AS c 
FROM ocjenjivanje AS o
WHERE o.Ocjena NOT IN (SELECT Min(Ocjena) FROM ocjenjivanje UNION SELECT Max(Ocjena) FROM ocjenjivanje)
GROUP BY Ocjena

---

谢谢1064-您的SQL语法有错误；检查与您的MySQL服务器版本对应的手册，以了解在第4行的“ON o.c m.l和o.c m.h LIMIT 0，25”附近使用的正确语法。由于您的努力，我将接受您的答案，但这并没有给我预期的结果。下面是我如何解决它的。当然是1，3，4！！！！！！！！！！！！！！！！！！但是这个查询返回Ocjena{2,3,4}，而不是重复次数最多和最少的值。。。