Mysql 如何使用JOIN和WHERE语句筛选记录？

我的问题

SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
   FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid 
LEFT JOIN table5 ON table1.name = table5.position
**LEFT JOIN vacation on vacation.userid = table1.userid
WHERE vacation.userid IS NULL**;

这将选择用户ID不在休假表中的所有位置

---

现在，我需要检查userid是否在休假表中，并且如果此

userid

的

vacation.status=1

仍应显示在查询中。

如果这是一个单独的查询/要求，则以下查询将起作用：

SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
   FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid 
INNER JOIN vacation on vacation.userid = table1.userid
LEFT JOIN table5 ON table1.name = table5.position
WHERE vacation.status = 1;

如果您同时需要这两个要求（userid为NULL或status=1），请尝试以下操作：

SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
   FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid 
LEFT JOIN table5 ON table1.name = table5.position
LEFT JOIN vacation on vacation.userid = table1.userid
WHERE vacation.user_id IS NULL or vacation.status = 1;

---

它需要是相同的查询，我尝试过，但它没有为我首先工作，现在它与您的例子，谢谢兄弟工作。