Mysql 选择在一列中共享公共值但被其他值选中的行

我的示例表：

汽车选择

| ID | CAR_ID |    DESCRIPTION |
|----|--------|----------------|
|  1 |      5 | tinted windows |
|  2 |      5 |  power windows |
|  3 |      6 |  power windows |
|  4 |      7 | tinted windows |

---

如何编写一条sql语句，获取输入“着色窗”和“电动窗”，并返回第1行和第2行（它们在car\u id列中共享一个公共值）？

使用

WHERE

获取与输入匹配的所有行，然后

按

对每个输入至少有一行的car\u id

进行分组。您可以使用下面的查询来执行此操作

SELECT car_id 
FROM CarOptions
WHERE (description = "tinted windows" OR 
       description = "power windows")
GROUP BY car_id
HAVING SUM(description = "tinted windows") > 0 AND 
       SUM(description = "power windows") > 0

看

要得到整排你可以做的

SELECT *
FROM CarOptions
WHERE car_id IN (
  SELECT car_id
  FROM CarOptions
  WHERE (description = "tinted windows" OR
         description = "power windows")
  GROUP BY car_id
  HAVING SUM(description = "tinted windows") > 0 AND
         SUM(description = "power windows") > 0)

在这种特殊情况下，您可以

SELECT * 
  FROM caroptions o JOIN
(
  SELECT car_id
    FROM caroptions
   WHERE description IN('tinted windows', 'power windows')
   GROUP BY car_id
  HAVING COUNT(DISTINCT description) = 2
) q  
    ON o.car_id = q.car_id

输出：

| ID | CAR_ID |    DESCRIPTION |
|----|--------|----------------|
|  1 |      5 | tinted windows |
|  2 |      5 |  power windows |
|ID |汽车ID |描述|
|----|--------|----------------|
|1 | 5 |有色窗户|
|2 | 5 |电动车窗|
这里是演示
@user2775071它有帮助吗？