mysql在一个数据库中选择不同的查询

如何通过一个查询获得以下信息： 我想从我的评论表中了解所有人对给定帖子id的评论情况，然后根据用户的姓名检查用户发表评论的次数。我想避免对它有两种不同的查询

我一直在尝试以下方法，但不会返回预期结果

SELECT comments.*, COUNT(approved.comment_approved) AS has_commented  FROM wp_comments AS comments  
    INNER JOIN wp_comments AS approved 
    ON comments.comment_author = approved.comment_author

WHERE comments.comment_post_ID =14616
GROUP BY comments.comment_content

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您不应该按

post\u ID

分组吗？（只返回一行）

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或者，您希望每个“已批准”的评论都有一行吗？

您能告诉我们预期的结果和当前的结果吗？更好地建立一个

SELECT
  comments.*
, COUNT(approved.comment_approved) AS "has_commented"
FROM wp_comments AS comments
JOIN wp_comments AS approved
  ON (comments.comment_author = approved.comment_author)
WHERE comments.comment_post_ID = 14616
GROUP BY comments.comment_post_ID
;