在Neo4j中查找具有相同相关节点的节点
我有一个数据库,包含以下模式中的科学论文和相应作者:在Neo4j中查找具有相同相关节点的节点,neo4j,cypher,Neo4j,Cypher,我有一个数据库,包含以下模式中的科学论文和相应作者: (a:Author {id:1})-[:WROTE]->(p:Paper {title:"XY"})<-[:WROTE]-(b:Author {id:2}) 要删除重复项,可以添加如下所示的WHERE子句: MATCH (a:Author)-[:WROTE]->(p:Paper)<-[:WROTE]-(b:Author) WHERE id(a) > id(b) WITH a, b, COUNT(p) AS co
(a:Author {id:1})-[:WROTE]->(p:Paper {title:"XY"})<-[:WROTE]-(b:Author {id:2})
要删除重复项,可以添加如下所示的
WHERE
子句:
MATCH (a:Author)-[:WROTE]->(p:Paper)<-[:WROTE]-(b:Author)
WHERE id(a) > id(b)
WITH a, b, COUNT(p) AS count
ORDER BY count DESC
RETURN a.name, b.name, count
LIMIT 10
匹配(a:作者)-[:编写]->(p:论文)id(b)
用a,b,COUNT(p)作为计数
按计数顺序描述
返回a.name、b.name、count
限制10
MATCH (a:Author)-[:WROTE]->(p:Paper)<-[:WROTE]-(b:Author)
WITH a, b, collect(p) AS paper, COUNT(p) AS count
ORDER BY count DESC
LIMIT 10
RETURN a, b, paper
MATCH (a:Author)-[:WROTE]->(p:Paper)<-[:WROTE]-(b:Author)
WHERE id(a) > id(b)
WITH a, b, COUNT(p) AS count
ORDER BY count DESC
RETURN a.name, b.name, count
LIMIT 10