使用RETURN语句中的计算进行Neo4J查询

我有一个简单的模型：

(teacher)-[:HAD]->(contract)-[:WITH]-(school)

一名教师可以与同一所学校或其他学校签订多份合同。现在，合同上的一个属性是

{leadership:'Senior Leader'}

，我试图查询所有高级领导，以了解他们与多少所学校签订了合同

//FIND ALL HEADS AND NUMBER OF SCHOOLS THEY WENT TO
MATCH (t:Teacher)
WHERE (t)-[:HAD]->(:Contract {leadership: 'Head'})
MATCH (t)-[:HAD]->(:Contract)-[:WITH]->(s:School)
RETURN t,count(distinct(s)) as nr_of_schools
ORDER BY nr_of_schools DESC

我想在计算中使用

nr\u学校

：

toFloat(no_of_schools) / count(distinct(t))*100
ORDER BY toFloat(no_of_schools) / count(distinct(t))*100 DESC

---

本质上，我是在发现70%的班主任去了一所学校，20%的班主任去了两所学校，其余的去了三所学校之后。我想我可以使用

no\u of_schools

作为参数，但我认为这是不可能的。

您可以使用

和

进行中间计算：

//FIND ALL HEADS AND NUMBER OF SCHOOLS THEY WENT TO
MATCH (t:Teacher)
WHERE (t)-[:HAD]->(:Contract {leadership: 'Head'})
MATCH (t)-[:HAD]->(:Contract)-[:WITH]->(s:School)
WITH t,count(distinct(s)) as no_of_schools
RETURN toFloat(no_of_schools) / count(distinct(t))*100 AS ratio
ORDER BY ratio DESC

MATCH (t:Teacher)
WITH count(t) as tCount // don't need distinct here, but wouldn't hurt
MATCH (t:Teacher)
WHERE (t)-[:HAD]->(:Contract {leadership: 'Head'})
MATCH (t)-[:HAD]->(:Contract)-[:WITH]->(s:School)
WITH t,tCount,count(distinct(s)) as no_of_schools
RETURN toFloat(no_of_schools) / tCount*100 AS ratio
ORDER BY ratio DESC

如果要返回

t

，返回的比率需要稍微重写一下查询-不能同时返回变量和变量上的聚合-

返回t，则无法计数（t）

MATCH (t:Teacher)
WITH count(t) as tCount // don't need distinct here, but wouldn't hurt
MATCH (t:Teacher)
WHERE (t)-[:HAD]->(:Contract {leadership: 'Head'})
MATCH (t)-[:HAD]->(:Contract)-[:WITH]->(s:School)
WITH t,tCount,count(distinct(s)) as no_of_schools
RETURN toFloat(no_of_schools) / tCount*100 AS ratio
ORDER BY ratio DESC