如何在mongodb中使用node.js删除嵌入（嵌套）文档

这是我的模式…

 const commentSchema = new mongoose.Schema({
      comment: String,
      imagename:String
    });
    const Comment  =  new mongoose.model("Comment",commentSchema);



    const userSchema = new mongoose.Schema({
      email: String,
      password:String,
      comments: [commentSchema]

    });
    userSchema.plugin(passportLocalMongoose);
    const User = new mongoose.model("User", userSchema);

  app.post("/delete", function(req,res){
      if(req.isAuthenticated()) {
        User.findById(req.user.id,function(err, foundUser){
          if(err){
            console.log(err);
          }
          else{
            const uid = foundUser.id;                 //this is the User iD
         const checkedItemId = (req.body.checkbox);  //this is the comment ID
         console.log(checkedItemId);

    User.updateOne(_id:"uid","comments._id": checkedItemId},{$pull :{comments:{_id :checkedItemId}}});
     User.Comment.pull(checkedItemId);
            if(!err){
              console.log("successfully deleted");
     res.redirect("data")

            }

       }
       });
    }
    else{
     res.redirect("/");
    }
    });

"_id" : ObjectId("5eb798bb64d8f94df08a6ae7"), 
    "username" : "random", 
    "comments" : [
        {
            "_id" : ObjectId("5eb798cd64d8f94df08a6ae8"), 
            "comment" : "hello", 
            "imagename" : "image-1589090509389.jpeg"
        }
    ]

EDIT: After this question I got to know that there are 2 ways to solve this question, one is embedded and the other is a reference.
previously all the answers were dependent on the embedded model in the schema, and this question works on the reference model.

我正在尝试使用…删除嵌入的文档。

 const commentSchema = new mongoose.Schema({
      comment: String,
      imagename:String
    });
    const Comment  =  new mongoose.model("Comment",commentSchema);



    const userSchema = new mongoose.Schema({
      email: String,
      password:String,
      comments: [commentSchema]

    });
    userSchema.plugin(passportLocalMongoose);
    const User = new mongoose.model("User", userSchema);

  app.post("/delete", function(req,res){
      if(req.isAuthenticated()) {
        User.findById(req.user.id,function(err, foundUser){
          if(err){
            console.log(err);
          }
          else{
            const uid = foundUser.id;                 //this is the User iD
         const checkedItemId = (req.body.checkbox);  //this is the comment ID
         console.log(checkedItemId);

    User.updateOne(_id:"uid","comments._id": checkedItemId},{$pull :{comments:{_id :checkedItemId}}});
     User.Comment.pull(checkedItemId);
            if(!err){
              console.log("successfully deleted");
     res.redirect("data")

            }

       }
       });
    }
    else{
     res.redirect("/");
    }
    });

"_id" : ObjectId("5eb798bb64d8f94df08a6ae7"), 
    "username" : "random", 
    "comments" : [
        {
            "_id" : ObjectId("5eb798cd64d8f94df08a6ae8"), 
            "comment" : "hello", 
            "imagename" : "image-1589090509389.jpeg"
        }
    ]

EDIT: After this question I got to know that there are 2 ways to solve this question, one is embedded and the other is a reference.
previously all the answers were dependent on the embedded model in the schema, and this question works on the reference model.

>我想删除一条评论：hello和相关图像。

 const commentSchema = new mongoose.Schema({
      comment: String,
      imagename:String
    });
    const Comment  =  new mongoose.model("Comment",commentSchema);



    const userSchema = new mongoose.Schema({
      email: String,
      password:String,
      comments: [commentSchema]

    });
    userSchema.plugin(passportLocalMongoose);
    const User = new mongoose.model("User", userSchema);

  app.post("/delete", function(req,res){
      if(req.isAuthenticated()) {
        User.findById(req.user.id,function(err, foundUser){
          if(err){
            console.log(err);
          }
          else{
            const uid = foundUser.id;                 //this is the User iD
         const checkedItemId = (req.body.checkbox);  //this is the comment ID
         console.log(checkedItemId);

    User.updateOne(_id:"uid","comments._id": checkedItemId},{$pull :{comments:{_id :checkedItemId}}});
     User.Comment.pull(checkedItemId);
            if(!err){
              console.log("successfully deleted");
     res.redirect("data")

            }

       }
       });
    }
    else{
     res.redirect("/");
    }
    });

"_id" : ObjectId("5eb798bb64d8f94df08a6ae7"), 
    "username" : "random", 
    "comments" : [
        {
            "_id" : ObjectId("5eb798cd64d8f94df08a6ae8"), 
            "comment" : "hello", 
            "imagename" : "image-1589090509389.jpeg"
        }
    ]

EDIT: After this question I got to know that there are 2 ways to solve this question, one is embedded and the other is a reference.
previously all the answers were dependent on the embedded model in the schema, and this question works on the reference model.

当用户单击ejs页面上的按钮时，我试图删除用户中选定的注释。 它自动生成注释id，用户id使用身份验证生成。 因此，使用注释id和用户id，如何使用node.js删除MongoDB中的注释。我尝试了updateOne和pull，但不起作用。

 const commentSchema = new mongoose.Schema({
      comment: String,
      imagename:String
    });
    const Comment  =  new mongoose.model("Comment",commentSchema);



    const userSchema = new mongoose.Schema({
      email: String,
      password:String,
      comments: [commentSchema]

    });
    userSchema.plugin(passportLocalMongoose);
    const User = new mongoose.model("User", userSchema);

  app.post("/delete", function(req,res){
      if(req.isAuthenticated()) {
        User.findById(req.user.id,function(err, foundUser){
          if(err){
            console.log(err);
          }
          else{
            const uid = foundUser.id;                 //this is the User iD
         const checkedItemId = (req.body.checkbox);  //this is the comment ID
         console.log(checkedItemId);

    User.updateOne(_id:"uid","comments._id": checkedItemId},{$pull :{comments:{_id :checkedItemId}}});
     User.Comment.pull(checkedItemId);
            if(!err){
              console.log("successfully deleted");
     res.redirect("data")

            }

       }
       });
    }
    else{
     res.redirect("/");
    }
    });

"_id" : ObjectId("5eb798bb64d8f94df08a6ae7"), 
    "username" : "random", 
    "comments" : [
        {
            "_id" : ObjectId("5eb798cd64d8f94df08a6ae8"), 
            "comment" : "hello", 
            "imagename" : "image-1589090509389.jpeg"
        }
    ]

EDIT: After this question I got to know that there are 2 ways to solve this question, one is embedded and the other is a reference.
previously all the answers were dependent on the embedded model in the schema, and this question works on the reference model.

---

您正在查询中以字符串形式传递注释id和用户id，这将不起作用，您需要将其转换为ObjectId，请检查下面的更新代码

var mongoose = require('mongoose');

app.post("/delete", function(req,res){
  if(req.isAuthenticated()) {
    User.findById(req.user.id,function(err, foundUser){
      if(err){
        console.log(err);
      }
      else{
        const uid = foundUser.id;                 //this is the User iD
        const checkedItemId = mongoose.Types.ObjectId(req.body.checkbox);  //this is the comment ID
        console.log(checkedItemId);

        User.updateOne({_id: uid},{$pull :{comments:{_id :checkedItemId}}}, function(err, results){
          if(!err){
            console.log("successfully deleted");
            res.redirect("data")
          } else {
            console.log("error in deletion");
            res.redirect("/");
          }
        });
      }
    });
  } else {
    res.redirect("/");
  }
});

---

在上面的代码中，您正在从findbyId函数中获取ObjecId格式的用户id，只需不在其上添加“”，并将注释id转换为OBJEID格式

如果下面的答案之一回答了您的问题，按照此网站的工作方式，您将“接受”并“投票”答案，更多信息：。但前提是你的问题真的得到了回答。如果不是，考虑在问题中增加更多的细节，这应该回答你的问题，确保你在提问之前进行搜索。这能回答你的问题吗？谢谢你的反馈！声誉低于15的人所投的票会被记录下来，但不会改变公开显示的帖子分数。@Puneethingh。我已经检查了你的回复@aldokkani，但我猜他已经使用了引用方法，我在嵌入方法上的代码世界，以前不知道mongoose.Types.ObjectId（req.body.checkbox）。嗨，bhai，我想把你搜遍我怀疑你是否能找到答案。。User.findById这是一个额外的调用，您可以在不使用“User.findById”的情况下执行相同的调用。。在内部查询mongoose.Types.ObjectId（req.user.id）中使用此选项