Node.js Jest如何测试express API POST请求？

我需要使用Jest测试测试我对端点的POST请求是否正常工作。我的想法是首先获取服务表的计数（我正在使用sequelize orm），然后发送一个新的post请求，最后获取新的计数，并比较旧计数+1是否等于新计数，如果为真，则post请求工作正常

test('Create a valid Service', async (done) => {
const service = {
    name: "cool",
    description: "description"
};

await Service.count().then(async function (count) {

    await request(app)
        .post('/api/services')
        .send(service)
        .then(async () => {
            await Service.count().then(function (newcount) {
                expect(newcount).toBe(count + 1);
            });
        })
        .catch(err => console.log(`Error ${err}`));
});

}))

对我来说，测试看起来不错，但当我运行它时，我得到：

Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.

---

是否缺少某些内容，或者是否有更好的方法来测试POST请求？使用Jest？

是因为您没有调用Jest回调函数中传递的done回调。可以这样做

test('Create a valid Service', async(done) => {
    const service = {
        name: "cool",
        description: "description"
    };

    await Service.count().then(async function (count) {

        await request(app)
            .post('/api/services')
            .send(service)
            .then(async() => {
                await Service.count().then(function (newcount) {
                    expect(newcount).toBe(count + 1);
                    // execute done callback here
                    done();
                });
            })
            .catch(err => {
                // write test for failure here
                console.log(`Error ${err}`)
                done()
            });
    });
});

您也可以用这种方式编写此代码，以便提高可读性并最大限度地利用异步/await

test('Create a valid Service', async(done) => {
    const service = {
        name: "cool",
        description: "description"
    };
    try {
        const count = await Service.count();
        await request(app).post('/api/services').send(service)
        const newCount = await Service.count()
        expect(newCount).toBe(count + 1);
        done()
    } catch (err) {
        // write test for failure here
        console.log(`Error ${err}`)
        done()
    }
});

默认情况下，Jest还解析异步/等待情况下的承诺。我们也可以在不使用回调函数的情况下实现这一点

test('Create a valid Service', async() => {
    const service = {
        name: "cool",
        description: "description"
    };
    try {
        const count = await Service.count();
        await request(app).post('/api/services').send(service)
        const newCount = await Service.count()
        expect(newCount).toBe(count + 1);
    } catch (err) {
        // write test for failure here
        console.log(`Error ${err}`)
    }
});

---

非常感谢你！请你投票表决我的问题好吗？