Node.js Q Promise NodeJ如何解决循环中的问题
我有用nodejs编写的代码,使用Node.js Q Promise NodeJ如何解决循环中的问题,node.js,loops,promise,q,Node.js,Loops,Promise,Q,我有用nodejs编写的代码,使用Q承诺让我感到困惑 theFunction() .then(function(data) { var deferred = Q.defer() var result = []; for(i=0; i < data.length; i++) { secondFunc(data.item) .then(function(data2) { data.more = data2.ite
Q承诺让我感到困惑
theFunction()
.then(function(data) {
var deferred = Q.defer()
var result = [];
for(i=0; i < data.length; i++) {
secondFunc(data.item)
.then(function(data2) {
data.more = data2.item
});
result.push(data);
}
deferred.resolve(result);
deferred.promise();
});
就这样
[
{
id: 1,
item: 1,
hero: 2
},
{
id: 1,
item: 1,
hero: 2
}
]
[
{
id: 1,
item: 1,
hero: 2,
more: {
list: 1
}
},
{
id: 1,
item: 1,
hero: 2,
more: {
list: 4
}
}
]
我尝试了几种方法,首先输入命令
deferred.resolve();语句,仅显示1个数据
有什么解决方案吗?而不是延迟的
解决方法()
在将立即解决的数组上,使用等待承诺数组的Q.all
:
theFunction()
.then(function(data) {
var result = [];
for(var i=0; i < data.length; i++) (function(i){
result.push(secondFunc(data[i].item)
.then(function(data2) {
data[i].more = data2.item;
return data[i];
}));
})(i); // avoid the closure loop problem
return Q.all(result)
});
我知道这是一个老帖子,但我有同样的问题,并没有找到任何解决办法。也许这里有人能很快找到一个好的解决方案
function CompareTeamspeakClients(forumUsers) {
var promises = [];
var tsClient = new TeamSpeakClient("127.0.0.1", 10011);
tsClient.send("login", {
client_login_name: "serveradmin",
client_login_password: "M+h8YzUA"
}, function(err, response){
if (err) deferred.reject(err);
});
tsClient.send("use", {
port: 9987
}, function(err, response){
if (err) deferred.reject(err);
});
forumUsers.forEach(function(user, index){
var deferred = Q.defer();
tsClient.send("clientdbfind", ["uid"], {
pattern: user.tsid
}, function(err, response){
if (err) deferred.reject(err);
if (response) {
tsClient.send("clientdbinfo", {
cldbid: response.cldbid
}, function(err, response){
if (err) deferred.reject(err);
forumUsers[index]['tsdbid'] = response.client_database_id;
forumUsers[index]['tsnickname'] = response.client_nickname;
forumUsers[index]['tslastconnected'] = response.client_lastconnected;
deferred.resolve(forumUsers);
});
}
});
promises.push(deferred.promise);
});
console.log(promises);
return Q.all(promises);
}
THNAK的第二个代码工作正常,在
结果上几乎没有错误。map
应该是数据。map
function CompareTeamspeakClients(forumUsers) {
var promises = [];
var tsClient = new TeamSpeakClient("127.0.0.1", 10011);
tsClient.send("login", {
client_login_name: "serveradmin",
client_login_password: "M+h8YzUA"
}, function(err, response){
if (err) deferred.reject(err);
});
tsClient.send("use", {
port: 9987
}, function(err, response){
if (err) deferred.reject(err);
});
forumUsers.forEach(function(user, index){
var deferred = Q.defer();
tsClient.send("clientdbfind", ["uid"], {
pattern: user.tsid
}, function(err, response){
if (err) deferred.reject(err);
if (response) {
tsClient.send("clientdbinfo", {
cldbid: response.cldbid
}, function(err, response){
if (err) deferred.reject(err);
forumUsers[index]['tsdbid'] = response.client_database_id;
forumUsers[index]['tsnickname'] = response.client_nickname;
forumUsers[index]['tslastconnected'] = response.client_lastconnected;
deferred.resolve(forumUsers);
});
}
});
promises.push(deferred.promise);
});
console.log(promises);
return Q.all(promises);
}