Objective c 将浮点数四舍五入到目标C中的下一个整数？

在目标C中，如何将浮点值舍入到下一个整数值

1.1 -> 2
2.3 -> 3
3.4 -> 4
3.5 -> 4
3.6 -> 4
1.0000000001 -> 2

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你想要天花板功能。这样使用：

float roundedup = ceil(otherfloat);

使用

ceil（）

函数

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有人在目标C中做了一点数学题：

就是无法评论戴维斯的答案。他的第二个答案不起作用，因为模对浮点值不起作用。看起来不是吗

if (originalFloat - (int)originalFloat > 0) {
    originalFloat += 1;
    round = (int)originalFloat;
}

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综述StringFloat备注（这不是最好的方法）
语言-Swift&Objective C|xCode-9.1
我所做的是转换string>float>ceil>int>float>string
字符串浮动10.8->11.0
字符串浮动10.4->10.0

Swift

var AmountToCash1 = "7350.81079101"
AmountToCash1 = "\(Float(Int(ceil(Float(AmountToCash1)!))))"
print(AmountToCash1) // 7351.0


var AmountToCash2 = "7350.41079101"
AmountToCash2 = "\(Float(Int(ceil(Float(AmountToCash2)!))))"
print(AmountToCash2) // 7350.0

目标C

NSString *AmountToCash1 = @"7350.81079101";
AmountToCash1 = [NSString stringWithFormat:@"%f",float(int(ceil(AmountToCash1.floatValue)))];

func roundupFloatString(value:String)->String{
  var result = ""
  result = "\(Float(Int(ceil(Float(value)!))))"
  return result
}

-(NSString*)roundupFloatString:(NSString *)value{
    NSString *result = @"";
    result = [NSString stringWithFormat:@"%f",float(int(ceil(value.floatValue)))];
  return result;
}

或
您可以像这样创建一个自定义函数 Swift

NSString *AmountToCash1 = @"7350.81079101";
AmountToCash1 = [NSString stringWithFormat:@"%f",float(int(ceil(AmountToCash1.floatValue)))];

func roundupFloatString(value:String)->String{
  var result = ""
  result = "\(Float(Int(ceil(Float(value)!))))"
  return result
}

-(NSString*)roundupFloatString:(NSString *)value{
    NSString *result = @"";
    result = [NSString stringWithFormat:@"%f",float(int(ceil(value.floatValue)))];
  return result;
}

这样称呼它

    AmountToCash = self.roundupFloatString(value: AmountToCash)

    AmountToCash = [self roundupFloatString:AmountToCash];

目标C

NSString *AmountToCash1 = @"7350.81079101";
AmountToCash1 = [NSString stringWithFormat:@"%f",float(int(ceil(AmountToCash1.floatValue)))];

func roundupFloatString(value:String)->String{
  var result = ""
  result = "\(Float(Int(ceil(Float(value)!))))"
  return result
}

-(NSString*)roundupFloatString:(NSString *)value{
    NSString *result = @"";
    result = [NSString stringWithFormat:@"%f",float(int(ceil(value.floatValue)))];
  return result;
}

这样称呼它

    AmountToCash = self.roundupFloatString(value: AmountToCash)

    AmountToCash = [self roundupFloatString:AmountToCash];

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祝你好运！欢迎光临！支持我的回答

这表明我不相信我读到的第一份文档。你是对的。注意在函数中放一个浮点数。天花板（（宽度/100.）*7.）起作用。天花板（（宽度/100）*7）不