Objective c Swift中GCD后的调度?
我浏览了苹果公司的网站,找不到它的任何定义: 有人能解释一下Objective c Swift中GCD后的调度?,objective-c,swift,grand-central-dispatch,Objective C,Swift,Grand Central Dispatch,我浏览了苹果公司的网站,找不到它的任何定义: 有人能解释一下后调度单元的结构吗 dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>) (,)之后的调度 更清楚地了解结构: dispatch_after(when: dispatch_time_t, queue: dispatch_queue_t, block:
后调度单元的结构吗
dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)
(,)之后的调度
更清楚地了解结构:
dispatch_after(when: dispatch_time_t, queue: dispatch_queue_t, block: dispatch_block_t?)
dispatch\u time\t
是一个UInt64
。dispatch\u queue\t
实际上是一个名为NSObject
的类型别名,但是您应该使用熟悉的GCD方法来获取队列。这座街区很快就关闭了。具体而言,调度块
定义为()->Void
,相当于()->()
用法示例:
let delayTime = dispatch_time(DISPATCH_TIME_NOW, Int64(1 * Double(NSEC_PER_SEC)))
dispatch_after(delayTime, dispatch_get_main_queue()) {
print("test")
}
编辑:
我建议使用
编辑2:
在Swift 3中,将为GCD提供新的包装。请看这里:
原始示例将在Swift 3中编写如下:
let deadlineTime = DispatchTime.now() + .seconds(1)
DispatchQueue.main.asyncAfter(deadline: deadlineTime) {
print("test")
}
请注意,您可以将deadlineTime
声明编写为DispatchTime.now()+1.0
,并获得相同的结果,因为+
运算符被覆盖如下(类似于-
):
func+(时间:DispatchTime,秒数:双)->DispatchTime
func+(时间:DispatchWalltime,间隔:DispatchTimeInterval)->DispatchWalltime
这意味着,如果您不使用
DispatchTimeInterval
enum
只写一个数字,则假定您使用的是秒。Swift 3+
这在Swift 3+中非常简单和优雅:
DispatchQueue.main.asyncAfter(deadline: .now() + 4.5) {
// ...
}
旧答案:
为了扩展Cezary的答案,它将在1纳秒后执行,我必须在4.5秒后执行以下操作
let delay = 4.5 * Double(NSEC_PER_SEC)
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay))
dispatch_after(time, dispatch_get_main_queue(), block)
编辑:我发现我原来的代码有点错误。如果未将NSEC_PER_second强制转换为Double,则隐式键入会导致编译错误
如果有人能提出一个更为优化的解决方案,我会非常乐意听到。我经常在之后使用
dispatch\u,因此我编写了一个顶级实用函数来简化语法:
func delay(delay:Double, closure:()->()) {
dispatch_after(
dispatch_time(
DISPATCH_TIME_NOW,
Int64(delay * Double(NSEC_PER_SEC))
),
dispatch_get_main_queue(), closure)
}
现在你可以这样说:
delay(0.4) {
// do stuff
}
extension Double {
var dispatchTime: dispatch_time_t {
get {
return dispatch_time(DISPATCH_TIME_NOW,Int64(self * Double(NSEC_PER_SEC)))
}
}
}
dispatch_after(Double(2.0).dispatchTime, dispatch_get_main_queue(), { () -> Void in
self.dismissViewControllerAnimated(true, completion: nil)
})
delay(bySeconds: 1.5) {
// delayed code
}
哇,这是一种可以提高语言水平的语言。还有什么更好的
Swift 3、Xcode 8和Seed 6的更新
现在他们已经改进了调用语法,似乎不值得费心:
func delay(_ delay:Double, closure:@escaping ()->()) {
let when = DispatchTime.now() + delay
DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}
非常好,如果需要使块无效,您可能希望使用以下方法:
typealias dispatch_cancelable_closure = (cancel : Bool) -> Void
func delay(time:NSTimeInterval, closure:()->Void) -> dispatch_cancelable_closure? {
func dispatch_later(clsr:()->Void) {
dispatch_after(
dispatch_time(
DISPATCH_TIME_NOW,
Int64(time * Double(NSEC_PER_SEC))
),
dispatch_get_main_queue(), clsr)
}
var closure:dispatch_block_t? = closure
var cancelableClosure:dispatch_cancelable_closure?
let delayedClosure:dispatch_cancelable_closure = { cancel in
if closure != nil {
if (cancel == false) {
dispatch_async(dispatch_get_main_queue(), closure!);
}
}
closure = nil
cancelableClosure = nil
}
cancelableClosure = delayedClosure
dispatch_later {
if let delayedClosure = cancelableClosure {
delayedClosure(cancel: false)
}
}
return cancelableClosure;
}
func cancel_delay(closure:dispatch_cancelable_closure?) {
if closure != nil {
closure!(cancel: true)
}
}
使用如下
let retVal = delay(2.0) {
println("Later")
}
delay(1.0) {
cancel_delay(retVal)
}
上面的链接似乎已关闭 另一种方法是像这样扩展Double:
delay(0.4) {
// do stuff
}
extension Double {
var dispatchTime: dispatch_time_t {
get {
return dispatch_time(DISPATCH_TIME_NOW,Int64(self * Double(NSEC_PER_SEC)))
}
}
}
dispatch_after(Double(2.0).dispatchTime, dispatch_get_main_queue(), { () -> Void in
self.dismissViewControllerAnimated(true, completion: nil)
})
delay(bySeconds: 1.5) {
// delayed code
}
然后你可以这样使用它:
delay(0.4) {
// do stuff
}
extension Double {
var dispatchTime: dispatch_time_t {
get {
return dispatch_time(DISPATCH_TIME_NOW,Int64(self * Double(NSEC_PER_SEC)))
}
}
}
dispatch_after(Double(2.0).dispatchTime, dispatch_get_main_queue(), { () -> Void in
self.dismissViewControllerAnimated(true, completion: nil)
})
delay(bySeconds: 1.5) {
// delayed code
}
我喜欢matt的延迟函数,但出于偏好,我宁愿限制传递闭包。苹果公司在Objective-C的代码片段后有一个调度:
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(<#delayInSeconds#> * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
<#code to be executed after a specified delay#>
});
delay(bySeconds: 1.5, dispatchLevel: .background) {
// delayed code that will run on background thread
}
dispatch\u在(dispatch\u time(dispatch\u time\u NOW,(int64\u t)(*NSEC\u PER\u SEC)),dispatch\u get\u main\u queue()之后^{
});
下面是移植到Swift3的相同片段:
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + <#delayInSeconds#>) {
<#code to be executed after a specified delay#>
}
DispatchQueue.main.asyncAfter(截止日期:DispatchTime.now()+){
}
使用此代码在2.0秒后执行一些与UI相关的任务
let delay = 2.0
let delayInNanoSeconds = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
let mainQueue = dispatch_get_main_queue()
dispatch_after(delayInNanoSeconds, mainQueue, {
print("Some UI related task after delay")
})
Swift 3.0版
下面的闭包函数在主线程上延迟后执行一些任务
func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
onCompletion()
})
}
func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
onCompletion()
})
}
调用此函数,如下所示:
performAfterDelay(delay: 4.0) {
print("test")
}
performAfterDelay(delay: 4.0) {
print("test")
}
1) 将此方法添加为UIViewController扩展的一部分
extension UIViewController{
func runAfterDelay(delay: NSTimeInterval, block: dispatch_block_t) {
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
dispatch_after(time, dispatch_get_main_queue(), block)
}
}
在VC上调用此方法:
self.runAfterDelay(5.0, block: {
//Add code to this block
print("run After Delay Success")
})
(二)
(三)
//紧凑型
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 2), dispatch_get_main_queue()) {
//Code here
}
}
虽然不是OP的原始问题,但某些与NSTimer
相关的问题已被标记为该问题的副本,因此值得在此处包含NSTimer
答案
NSTimer
vsdispatch\u后
NSTimer
的级别更高,而dispatch\u after
的级别更低
NSTimer
更容易取消。在
之后取消dispatch\u需要写入
使用NSTimer延迟任务
创建一个NSTimer
实例
var timer = NSTimer()
以所需的延迟启动计时器
// invalidate the timer if there is any chance that it could have been called before
timer.invalidate()
// delay of 2 seconds
timer = NSTimer.scheduledTimerWithTimeInterval(2.0, target: self, selector: #selector(delayedAction), userInfo: nil, repeats: false)
添加一个要在延迟后调用的函数(使用上面选择器参数使用的任何名称)
笔记
- 如果需要在操作发生之前取消操作,只需调用
timer.invalidate()
- 对于重复操作,请使用
repeats:true
李>
- 如果您有一个不需要取消的一次性事件,则无需创建
计时器
实例变量。以下几点就足够了:
NSTimer.scheduledTimerWithTimeInterval(2.0, target: self, selector: #selector(delayedAction), userInfo: nil, repeats: false)
- 看我更完整的回答
另一个帮助程序,用于延迟使用率100%快速的代码,并允许选择不同的线程运行延迟的代码:
public func delay(bySeconds seconds: Double, dispatchLevel: DispatchLevel = .main, closure: @escaping () -> Void) {
let dispatchTime = DispatchTime.now() + seconds
dispatchLevel.dispatchQueue.asyncAfter(deadline: dispatchTime, execute: closure)
}
public enum DispatchLevel {
case main, userInteractive, userInitiated, utility, background
var dispatchQueue: DispatchQueue {
switch self {
case .main: return DispatchQueue.main
case .userInteractive: return DispatchQueue.global(qos: .userInteractive)
case .userInitiated: return DispatchQueue.global(qos: .userInitiated)
case .utility: return DispatchQueue.global(qos: .utility)
case .background: return DispatchQueue.global(qos: .background)
}
}
}
现在您只需在主线程上延迟代码,如下所示:
delay(0.4) {
// do stuff
}
extension Double {
var dispatchTime: dispatch_time_t {
get {
return dispatch_time(DISPATCH_TIME_NOW,Int64(self * Double(NSEC_PER_SEC)))
}
}
}
dispatch_after(Double(2.0).dispatchTime, dispatch_get_main_queue(), { () -> Void in
self.dismissViewControllerAnimated(true, completion: nil)
})
delay(bySeconds: 1.5) {
// delayed code
}
如果要将代码延迟到其他线程:
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(<#delayInSeconds#> * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
<#code to be executed after a specified delay#>
});
delay(bySeconds: 1.5, dispatchLevel: .background) {
// delayed code that will run on background thread
}
如果您更喜欢同样具有一些更方便功能的框架,请签出。您可以通过迦太基将其添加到您的项目中,然后像上面的示例一样使用它,例如:
import HandySwift
delay(bySeconds: 1.5) {
// delayed code
}
在Swift 3.0中
调度队列
DispatchQueue(label: "test").async {
//long running Background Task
for obj in 0...1000 {
print("async \(obj)")
}
// UI update in main queue
DispatchQueue.main.async(execute: {
print("UI update on main queue")
})
}
DispatchQueue(label: "m").sync {
//long running Background Task
for obj in 0...1000 {
print("sync \(obj)")
}
// UI update in main queue
DispatchQueue.main.sync(execute: {
print("UI update on main queue")
})
}
DispatchQueue.main.after(when: DispatchTime.now() + 5) {
print("Dispatch after 5 sec")
}
delayQueue.asyncAfter(deadline: .now() + 0.60) {
print(Date())
}
delayQueue.asyncAfter(deadline: .now() + additionalTime) {
print(Date())
}
5秒后发送
DispatchQueue(label: "test").async {
//long running Background Task
for obj in 0...1000 {
print("async \(obj)")
}
// UI update in main queue
DispatchQueue.main.async(execute: {
print("UI update on main queue")
})
}
DispatchQueue(label: "m").sync {
//long running Background Task
for obj in 0...1000 {
print("sync \(obj)")
}
// UI update in main queue
DispatchQueue.main.sync(execute: {
print("UI update on main queue")
})
}
DispatchQueue.main.after(when: DispatchTime.now() + 5) {
print("Dispatch after 5 sec")
}
delayQueue.asyncAfter(deadline: .now() + 0.60) {
print(Date())
}
delayQueue.asyncAfter(deadline: .now() + additionalTime) {
print(Date())
}
Swift 3.0、Swift 4.0和Swift 5.0中最简单的解决方案
func delayWithSeconds(_ seconds: Double, completion: @escaping () -> ()) {
DispatchQueue.main.asyncAfter(deadline: .now() + seconds) {
completion()
}
}
用法
Swift 3.0版
下面的闭包函数在主线程上延迟后执行一些任务
func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
onCompletion()
})
}
func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){
DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
onCompletion()
})
}
调用此函数,如下所示:
performAfterDelay(delay: 4.0) {
print("test")
}
performAfterDelay(delay: 4.0) {
print("test")
}
这对我有用
Swift 3:
let time1 = 8.23
let time2 = 3.42
// Delay 2 seconds
DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) {
print("Sum of times: \(time1 + time2)")
}
目标C:
CGFloat time1 = 3.49;
CGFloat time2 = 8.13;
// Delay 2 seconds
dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(2.0 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
CGFloat newTime = time1 + time2;
NSLog(@"New time: %f", newTime);
});
现在,Swift中的Grand Central Dispatch(GCD)中的异步调度已超过语法糖
添加播客文件
pod 'AsyncSwift'
然后,你可以像这样使用它
let seconds = 3.0
Async.main(after: seconds) {
print("Is called after 3 seconds")
}.background(after: 6.0) {
print("At least 3.0 seconds after previous block, and 6.0 after Async code is called")
}
我总是喜欢使用扩展而不是自由函数。
DispatchQueue.main.asyncAfter(deadline: .now() + 0.9) {
// Call your function 1
DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
// Call your function 2
}
}
*// Start your amination*
self.startAnimation()
DispatchQueue.main.asyncAfter(deadline: .now() + 0.9) {
*// The animation will execute depending on the delay time*
self.stopAnimation()
DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
*// Now update your view*
self.fetchData()
self.updateUI()
}
}
斯威夫特4
使用方法如下
DispatchQueue.performAction(after: 0.3) {
// Code Here
}
Swift 4有一个非常简单的方法:
Timer.scheduledTimer(withTimeInterval: 2, repeats: false) { (timer) in
// Your stuff here
print("hello")
}
Swift 3&4:
您可以创建一个扩展