Oracle pivot查询获取ora-00933
我想转换我的结果 这是我的成绩表:Oracle pivot查询获取ora-00933,oracle,pivot,rows,transpose,Oracle,Pivot,Rows,Transpose,我想转换我的结果 这是我的成绩表: CUMA 13:30 ORHAN SAVAS CUMA 14:00 FATMA ETA CUMA 14:30 ISMAHAN YALDIZ PAZARTESI 13:00 SEYHAN UNVER PAZARTESI 13:30 SELMA CALISKAN PAZARTESI 17:45 ESMA COMERT SALI
CUMA 13:30 ORHAN SAVAS
CUMA 14:00 FATMA ETA
CUMA 14:30 ISMAHAN YALDIZ
PAZARTESI 13:00 SEYHAN UNVER
PAZARTESI 13:30 SELMA CALISKAN
PAZARTESI 17:45 ESMA COMERT
SALI 09:45 SEYMA DURLANIK
SALI 10:00 HASAN GOC
SALI 13:00 TURKAN BICAK
SALI 14:30 ISMAHAN YALDIZ
PERSEMBE 08:30 ZUHRE YEL
PERSEMBE 08:48 AYSEL POLAT
PERSEMBE 09:00 AHMET OZGUNGOR
PERSEMBE 09:12 TELEFON RANDEVUSU
我可以这样转换我的结果表吗
CUMA PAZARTESI SALI PERSEMBE
13:30 ORHAN SAVAS 13:00 SEYHAN UNVER 09:45 SEYMA DURLANIK 08:30 ZUHRE YEL
14:00 FATMA ETA 13:30 SELMA CALISKAN 10:00 HASAN GOC 08:48 AYSEL POLAT
14:30 ISMAHAN YALDIZ 17:45 ESMA COMERT 13:00 TURKAN BICAK 09:00 AHMET OZGUNGOR
14:30 ISMAHAN YALDIZ 09:12 TELEFON RANDEVUSU
这是我的疑问:
WITH got_r_num AS
(
SELECT TO_CHAR (t.r_tarihi, 'DY') AS gun
, TO_CHAR (t.baslama, 'HH24:MI') AS saat
, h.adi || ' ' || h.soyadi AS hasta
, ROW_NUMBER () OVER ( PARTITION BY TO_CHAR (t.r_tarihi, 'DY')
ORDER BY t.baslama
) AS r_num
FROM randevu_entegre_deneme t
LEFT OUTER JOIN hasta_deneme h ON h.id = t.hasta_id
WHERE (r_tarihi BETWEEN TO_DATE ('20.5.2011', 'dd.mm.yyyy')
AND TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 9)
)
SELECT *
FROM got_r_num PIVOT ( MIN (SAAT) AS s , MIN (HASTA) AS h
FOR gun IN ( 'MON' AS monday
, 'TUE' AS tuesday
, 'WED' AS wednesday
, 'THU' AS thursday
, 'FRI' AS friday
)
)
ORDER BY r_num;
这是我的CREATETABLE和INSERT语句
create table RANDEVU_ENTEGRE_DENEME
(
hasta_id INTEGER,
baslama DATE,
R_TARIHI DATE
);
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (39733, to_date('24-05-2011 13:00:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('24-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (367216, to_date('23-05-2011 13:30:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('23-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (522956, to_date('20-05-2011 13:30:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('20-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (801923, to_date('23-05-2011 17:45:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('23-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (815746, to_date('24-05-2011 09:45:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('24-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (815746, to_date('20-05-2011 08:54:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('20-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (842677, to_date('20-05-2011 14:00:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('20-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (842677, to_date('24-05-2011 14:00:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('24-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (854143, to_date('26-05-2011 08:48:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('26-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (854559, to_date('23-05-2011 13:00:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('23-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (861624, to_date('20-05-2011 10:00:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('20-05-2011', 'dd-mm-yyyy'));
insert into RANDEVU_ENTEGRE_DENEME (hasta_id, baslama, r_tarihi)
values (868595, to_date('26-05-2011 08:30:00', 'dd-mm-yyyy hh24:mi:ss'), to_date('26-05-2011', 'dd-mm-yyyy'));
commit;
create table HASTA_DENEME
(
id INTEGER,
adi VARCHAR2(25),
soyadi VARCHAR2(25)
);
insert into HASTA_DENEME (id, adi, soyadi)
values (39733, 'TURKAN', 'BICAK');
insert into HASTA_DENEME (id, adi, soyadi)
values (367216, 'SELMA', 'CALISKAN');
insert into HASTA_DENEME (id, adi, soyadi)
values (522956, 'ORHAN', 'SAVAS');
insert into HASTA_DENEME (id, adi, soyadi)
values (801923, 'ESMA', 'COMERT');
insert into HASTA_DENEME (id, adi, soyadi)
values (815746, 'SEYMA', 'DURLANIK');
insert into HASTA_DENEME (id, adi, soyadi)
values (842677, 'FATMA', 'ETA');
insert into HASTA_DENEME (id, adi, soyadi)
values (854143, 'AYSEL', 'POLAT');
insert into HASTA_DENEME (id, adi, soyadi)
values (854559, 'SEYHAN', 'UNVER');
insert into HASTA_DENEME (id, adi, soyadi)
values (861624, 'SENGUL', 'AKBAS');
insert into HASTA_DENEME (id, adi, soyadi)
values (868595, 'ZUHRE', 'YEL');
commit;
我得到了ora-00933。如何修复..PIVOT操作符被禁用。尝试在10gR2中运行代码时出现错误:
FROM got_r_num PIVOT ( MIN (SAAT) AS s , MIN (HASTA) AS h
*
ERROR at line 15:
ORA-00933: SQL command not properly ended
在11g之前,您需要使用不同的机制
我想你想要这样的东西:
WITH got_r_num AS
(
SELECT TO_CHAR (t.r_tarihi, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') AS gun
, TO_CHAR (t.baslama, 'HH24:MI') AS saat
, h.adi || ' ' || h.soyadi AS hasta
, ROW_NUMBER () OVER ( PARTITION BY TO_CHAR (t.r_tarihi, 'DY')
ORDER BY t.baslama
) AS r_num
FROM randevu_entegre_deneme t
LEFT OUTER JOIN hasta_deneme h ON h.id = t.hasta_id
WHERE (r_tarihi BETWEEN TO_DATE ('20.5.2011', 'dd.mm.yyyy')
AND TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 9)
)
SELECT min(case when gun = 'MON' then SAAT ||' '|| HASTA end) as pazartesi
, min(case when gun = 'TUE' then SAAT ||' '|| HASTA end) as sali
, min(case when gun = 'WED' then SAAT ||' '|| HASTA end) as carsamba
, min(case when gun = 'THU' then SAAT ||' '|| HASTA end) as persembe
, min(case when gun = 'FRI' then SAAT ||' '|| HASTA end) as cuma
FROM got_r_num
GROUP BY r_num
ORDER BY r_num;
您发布的表格和insert语句提供:
PAZARTESI SALI CARSAMBA PERSEMBE CUMA
-------------------- -------------------- -------------------- -------------------- --------------------
13:00 SEYHAN UNVER 09:45 SEYMA DURLANIK 08:30 ZUHRE YEL 08:54 SEYMA DURLANIK
13:30 SELMA CALISKAN 13:00 TURKAN BICAK 08:48 AYSEL POLAT 10:00 SENGUL AKBAS
17:45 ESMA COMERT 14:00 FATMA ETA 13:30 ORHAN SAVAS
14:00 FATMA ETA
。。。这并不完全符合您所说的预期,但确实使用了pivot
与数据和BlueFoot的SQl Fiddle保持一致
我使用了你似乎期待的土耳其日标签;正如realspirituals所指出的,在发布问题时更改代码中的内容并不是完全有帮助的。语言差异在这里很重要,因为您的日常比较是假设DY
格式是某种语言-无论您实际使用的是英语缩写还是土耳其语缩写都无关紧要,关键是您假设客户机和代码使用的是同一种语言。您可以通过强制使用特定语言的DY
来避免潜在的不匹配,这样您就知道您将对比什么;这就是它所做的,使用可选的第三个参数:
另外,我把它留作只报道五天,因为你似乎对周末不感兴趣。这似乎有点奇怪,虽然你有一个9天的日期跨度,因为这将包括其中的一些天多次,你将无法分辨出一个特定的时间是从哪个星期开始。你的r\u num
应该保持它们的顺序,因此如果你两周都有它们,你可能会发现时间顺序不正确,尽管它们也将基于日期。也许这就是你想要的
用于后续查询列的排序;您可以使用
密集秩
分配另一个伪列,并将其用于案例
,而不是枪
:
WITH got_r_num AS
(
SELECT TO_CHAR (t.r_tarihi, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') AS gun
, TO_CHAR (t.r_tarihi, 'DAY', 'NLS_DATE_LANGUAGE=TURKISH') AS d_name
, DENSE_RANK () OVER ( ORDER BY TRUNC( t.r_tarihi) ) AS d_num
, TO_CHAR (t.baslama, 'HH24:MI') AS saat
, h.adi || ' ' || h.soyadi AS hasta
, ROW_NUMBER () OVER ( PARTITION BY TO_CHAR (t.r_tarihi, 'DY')
ORDER BY t.baslama
) AS r_num
FROM randevu_entegre_deneme t
LEFT OUTER JOIN hasta_deneme h ON h.id = t.hasta_id
WHERE (r_tarihi BETWEEN TO_DATE ('20.5.2011', 'dd.mm.yyyy')
AND TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 9)
)
SELECT min(case when mod(d_num, 7) = 1 then SAAT ||' '|| HASTA end) as day1
, min(case when mod(d_num, 7) = 2 then SAAT ||' '|| HASTA end) as day2
, min(case when mod(d_num, 7) = 3 then SAAT ||' '|| HASTA end) as day3
, min(case when mod(d_num, 7) = 4 then SAAT ||' '|| HASTA end) as day4
, min(case when mod(d_num, 7) = 5 then SAAT ||' '|| HASTA end) as day5
, min(case when mod(d_num, 7) = 6 then SAAT ||' '|| HASTA end) as day6
, min(case when mod(d_num, 7) = 0 then SAAT ||' '|| HASTA end) as day7
FROM got_r_num
GROUP BY r_num
ORDER BY r_num;
DAY1 DAY2 DAY3 DAY4 DAY5 DAY6 DAY7
-------------------- -------------------- -------------------- -------------------- -------------------- -------------------- --------------------
08:54 SEYMA DURLANIK 13:00 SEYHAN UNVER 09:45 SEYMA DURLANIK 08:30 ZUHRE YEL
10:00 SENGUL AKBAS 13:30 SELMA CALISKAN 13:00 TURKAN BICAK 08:48 AYSEL POLAT
13:30 ORHAN SAVAS 17:45 ESMA COMERT 14:00 FATMA ETA
14:00 FATMA ETA
实际上,我不再使用gun
,但我保留了它,并添加了d_name
作为全天名称,尽管目前两个名称都没有被选中。这完全跳过了carsamba
列,因为它没有数据,这与您的问题所显示的内容相匹配。如果你知道哪一列是哪一列,这可能就是你想要的。不幸的是,您无法动态分配列别名,因此您不知道day1
实际上是cuma
。如果您想为carsamba
留出间隙,则可以计算每个日期与开始日期的偏移量:
, TRUNC( t.r_tarihi) - TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 1 AS d_num
但您仍然不知道第1列代表哪一天。你可以假装,但这取决于你是如何运作的。如果要从应用程序中提取数据,则还可以查询d_名称
,并使用该名称。从SQL*Plus中,如果重复查询并使用替换变量,则可以执行此操作,这可能会带来很大的开销,或者部分解决方案只是将它们作为单独的选择来选择,这也不理想:
column r_num noprint
set head off
WITH got_r_num AS
(
...
)
SELECT 0 as r_num
, min(case when mod(d_num, 7) = 1 then d_name end) as day1
, min(case when mod(d_num, 7) = 2 then d_name end) as day2
, min(case when mod(d_num, 7) = 3 then d_name end) as day3
, min(case when mod(d_num, 7) = 4 then d_name end) as day4
, min(case when mod(d_num, 7) = 5 then d_name end) as day5
, min(case when mod(d_num, 7) = 6 then d_name end) as day6
, min(case when mod(d_num, 7) = 0 then d_name end) as day7
FROM got_r_num
UNION ALL
SELECT r_num
, min(case when mod(d_num, 7) = 1 then SAAT ||' '|| HASTA end) as day1
, min(case when mod(d_num, 7) = 2 then SAAT ||' '|| HASTA end) as day2
, min(case when mod(d_num, 7) = 3 then SAAT ||' '|| HASTA end) as day3
, min(case when mod(d_num, 7) = 4 then SAAT ||' '|| HASTA end) as day4
, min(case when mod(d_num, 7) = 5 then SAAT ||' '|| HASTA end) as day5
, min(case when mod(d_num, 7) = 6 then SAAT ||' '|| HASTA end) as day6
, min(case when mod(d_num, 7) = 0 then SAAT ||' '|| HASTA end) as day7
FROM got_r_num
GROUP BY r_num
ORDER BY r_num;
CUMA PAZARTESI SALI PER¿EMBE
08:54 SEYMA DURLANIK 13:00 SEYHAN UNVER 09:45 SEYMA DURLANIK 08:30 ZUHRE YEL
10:00 SENGUL AKBAS 13:30 SELMA CALISKAN 13:00 TURKAN BICAK 08:48 AYSEL POLAT
13:30 ORHAN SAVAS 17:45 ESMA COMERT 14:00 FATMA ETA
14:00 FATMA ETA
PIVOT
操作符被激活。尝试在10gR2中运行代码时出现错误:
FROM got_r_num PIVOT ( MIN (SAAT) AS s , MIN (HASTA) AS h
*
ERROR at line 15:
ORA-00933: SQL command not properly ended
在11g之前,您需要使用不同的机制
我想你想要这样的东西:
WITH got_r_num AS
(
SELECT TO_CHAR (t.r_tarihi, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') AS gun
, TO_CHAR (t.baslama, 'HH24:MI') AS saat
, h.adi || ' ' || h.soyadi AS hasta
, ROW_NUMBER () OVER ( PARTITION BY TO_CHAR (t.r_tarihi, 'DY')
ORDER BY t.baslama
) AS r_num
FROM randevu_entegre_deneme t
LEFT OUTER JOIN hasta_deneme h ON h.id = t.hasta_id
WHERE (r_tarihi BETWEEN TO_DATE ('20.5.2011', 'dd.mm.yyyy')
AND TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 9)
)
SELECT min(case when gun = 'MON' then SAAT ||' '|| HASTA end) as pazartesi
, min(case when gun = 'TUE' then SAAT ||' '|| HASTA end) as sali
, min(case when gun = 'WED' then SAAT ||' '|| HASTA end) as carsamba
, min(case when gun = 'THU' then SAAT ||' '|| HASTA end) as persembe
, min(case when gun = 'FRI' then SAAT ||' '|| HASTA end) as cuma
FROM got_r_num
GROUP BY r_num
ORDER BY r_num;
您发布的表格和insert语句提供:
PAZARTESI SALI CARSAMBA PERSEMBE CUMA
-------------------- -------------------- -------------------- -------------------- --------------------
13:00 SEYHAN UNVER 09:45 SEYMA DURLANIK 08:30 ZUHRE YEL 08:54 SEYMA DURLANIK
13:30 SELMA CALISKAN 13:00 TURKAN BICAK 08:48 AYSEL POLAT 10:00 SENGUL AKBAS
17:45 ESMA COMERT 14:00 FATMA ETA 13:30 ORHAN SAVAS
14:00 FATMA ETA
。。。这并不完全符合您所说的预期,但确实使用了pivot
与数据和BlueFoot的SQl Fiddle保持一致
我使用了你似乎期待的土耳其日标签;正如realspirituals所指出的,在发布问题时更改代码中的内容并不是完全有帮助的。语言差异在这里很重要,因为您的日常比较是假设DY
格式是某种语言-无论您实际使用的是英语缩写还是土耳其语缩写都无关紧要,关键是您假设客户机和代码使用的是同一种语言。您可以通过强制使用特定语言的DY
来避免潜在的不匹配,这样您就知道您将对比什么;这就是它所做的,使用可选的第三个参数:
另外,我把它留作只报道五天,因为你似乎对周末不感兴趣。这似乎有点奇怪,虽然你有一个9天的日期跨度,因为这将包括其中的一些天多次,你将无法分辨出一个特定的时间是从哪个星期开始。你的r\u num
应该保持它们的顺序,因此如果你两周都有它们,你可能会发现时间顺序不正确,尽管它们也将基于日期。也许这就是你想要的
用于后续查询列的排序;您可以使用
密集秩
分配另一个伪列,并将其用于案例
,而不是枪
:
WITH got_r_num AS
(
SELECT TO_CHAR (t.r_tarihi, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') AS gun
, TO_CHAR (t.r_tarihi, 'DAY', 'NLS_DATE_LANGUAGE=TURKISH') AS d_name
, DENSE_RANK () OVER ( ORDER BY TRUNC( t.r_tarihi) ) AS d_num
, TO_CHAR (t.baslama, 'HH24:MI') AS saat
, h.adi || ' ' || h.soyadi AS hasta
, ROW_NUMBER () OVER ( PARTITION BY TO_CHAR (t.r_tarihi, 'DY')
ORDER BY t.baslama
) AS r_num
FROM randevu_entegre_deneme t
LEFT OUTER JOIN hasta_deneme h ON h.id = t.hasta_id
WHERE (r_tarihi BETWEEN TO_DATE ('20.5.2011', 'dd.mm.yyyy')
AND TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 9)
)
SELECT min(case when mod(d_num, 7) = 1 then SAAT ||' '|| HASTA end) as day1
, min(case when mod(d_num, 7) = 2 then SAAT ||' '|| HASTA end) as day2
, min(case when mod(d_num, 7) = 3 then SAAT ||' '|| HASTA end) as day3
, min(case when mod(d_num, 7) = 4 then SAAT ||' '|| HASTA end) as day4
, min(case when mod(d_num, 7) = 5 then SAAT ||' '|| HASTA end) as day5
, min(case when mod(d_num, 7) = 6 then SAAT ||' '|| HASTA end) as day6
, min(case when mod(d_num, 7) = 0 then SAAT ||' '|| HASTA end) as day7
FROM got_r_num
GROUP BY r_num
ORDER BY r_num;
DAY1 DAY2 DAY3 DAY4 DAY5 DAY6 DAY7
-------------------- -------------------- -------------------- -------------------- -------------------- -------------------- --------------------
08:54 SEYMA DURLANIK 13:00 SEYHAN UNVER 09:45 SEYMA DURLANIK 08:30 ZUHRE YEL
10:00 SENGUL AKBAS 13:30 SELMA CALISKAN 13:00 TURKAN BICAK 08:48 AYSEL POLAT
13:30 ORHAN SAVAS 17:45 ESMA COMERT 14:00 FATMA ETA
14:00 FATMA ETA
实际上,我不再使用gun
,但我保留了它,并添加了d_name
作为全天名称,尽管目前两个名称都没有被选中。这完全跳过了carsamba
列,因为它没有数据,这与您的问题所显示的内容相匹配。如果你知道哪一列是哪一列,这可能就是你想要的。不幸的是,您无法动态分配列别名,因此您不知道day1
实际上是cuma
。如果您想为carsamba
留出间隙,则可以计算每个日期与开始日期的偏移量:
, TRUNC( t.r_tarihi) - TO_DATE ('20.5.2011', 'dd.mm.yyyy') + 1 AS d_num
但您仍然不知道第1列代表哪一天。你可以假装,但这取决于你是如何运作的。如果要从应用程序中提取数据,则还可以查询d_名称
,并使用该名称。从SQL*Plus中,如果重复查询并使用替换变量,则可以执行此操作,这可能会带来很大的开销,或者