在Oracle 11g中从XMLType列选择时间戳时出错

我有两个Oracle 11g数据库，其中一个表包含一个XMLType列和一些测试数据，这些数据仅在分隔符中有所不同，时间戳的毫秒数为：

create table TEST_TIMESTAMP (
  ID  number(19,0) constraint "NN_TEST_TIMESTAMP_ID" not null,
  DOC xmltype      constraint "NN_TEST_TIMESTAMP_DOC" not null
);

insert into TEST_TIMESTAMP values ( 1, xmltype('<?xml version="1.0" encoding="utf-8"?><test><ts>2015-04-08T04:55:33.11</ts></test>'));
insert into TEST_TIMESTAMP values ( 2, xmltype('<?xml version="1.0" encoding="utf-8"?><test><ts>2015-04-08T04:55:33,11</ts></test>'));

我得到的错误是：

ORA-01858: a non-numeric character was found where a numeric was expected
01858. 00000 - "a non-numeric character was found where a numeric was expected"
*Cause: The input data to be converted using a date format model was
        incorrect.  The input data did not contain a number where a number was
        required by the format model.
*Action:   Fix the input data or the date format model to make sure the
           elements match in number and type.  Then retry the operation.

我发现这些数据库之间的唯一区别是：

DB1:version=11.2.0.1.0，NLS_CHARACTERSET=AL32UTF8->在文档2上失败 DB2:version=11.2.0.2.0，NLS_CHARACTERSET=WE8MSWIN1252->在文档1上失败 DB1具有我所期望的行为。有人知道为什么这些数据库的行为不同，以及如何在DB2中解决这个问题吗

提前感谢,，

---

Oliver

我猜两个数据库的nls\u时间戳格式不同

但是，我不会在XMLTABLE级别强制进行隐式转换，而是在select列表中进行显式转换：

with test_timestamp as (select 1 id, xmltype('<?xml version="1.0" encoding="utf-8"?><test><ts>2015-04-08T04:55:33.11</ts></test>') doc from dual union all
                        select 2 id, xmltype('<?xml version="1.0" encoding="utf-8"?><test><ts>2015-04-08T04:55:33,11</ts></test>') doc from dual)
select x.original,
       to_timestamp(x.original, 'yyyy-mm-dd"T"hh24:mi:ss,ff2') result
from   test_timestamp t,
       xmltable('/test' passing t.doc
                columns original varchar2(50) path 'ts') x;

ORIGINAL                                           RESULT                                            
-------------------------------------------------- --------------------------------------------------
2015-04-08T04:55:33.11                             08/04/2015 04:55:33.110000000
2015-04-08T04:55:33,11                             08/04/2015 04:55:33.110000000

---

注意，我发现使用ss.ff2是错误的，但ss.ff2处理这两种情况都很好。不过，我不确定这是否依赖于其他nls设置。

时间戳和日期格式nls\U TIME\U格式，nls\U Timestamp\U格式，nls\U TIME\U TZ\U格式，NLS_TIMESTAMP_TZ_格式在两个数据库上都是相同的。我希望使用隐式转换，因为这些XML文档来自外部源，并且时间戳格式可能不同，因此显式转换对我来说不可靠。我想，最后我将把这个转换移回应用层，并使用Java和JodaTime。

with test_timestamp as (select 1 id, xmltype('<?xml version="1.0" encoding="utf-8"?><test><ts>2015-04-08T04:55:33.11</ts></test>') doc from dual union all
                        select 2 id, xmltype('<?xml version="1.0" encoding="utf-8"?><test><ts>2015-04-08T04:55:33,11</ts></test>') doc from dual)
select x.original,
       to_timestamp(x.original, 'yyyy-mm-dd"T"hh24:mi:ss,ff2') result
from   test_timestamp t,
       xmltable('/test' passing t.doc
                columns original varchar2(50) path 'ts') x;

ORIGINAL                                           RESULT                                            
-------------------------------------------------- --------------------------------------------------
2015-04-08T04:55:33.11                             08/04/2015 04:55:33.110000000
2015-04-08T04:55:33,11                             08/04/2015 04:55:33.110000000