Oracle 如何将日期转换为周数
我需要每周做报告,但我的周数应该从每月的第一天开始 以下是我的示例数据:Oracle 如何将日期转换为周数,oracle,date,plsql,week-number,Oracle,Date,Plsql,Week Number,我需要每周做报告,但我的周数应该从每月的第一天开始 以下是我的示例数据: report_date Vol 01 nov 2014 23 03 nov 2014 34 16 nov 2014 56 30 nov 2014 44 期望输出 Week no Vol 1 57 2 56 3 0 4 44 希望它清楚 谢谢 select to_char(report_date, 'W'), sum(vol) from
report_date Vol
01 nov 2014 23
03 nov 2014 34
16 nov 2014 56
30 nov 2014 44
期望输出
Week no Vol
1 57
2 56
3 0
4 44
希望它清楚
谢谢
select to_char(report_date, 'W'), sum(vol)
from your_table
group by to_char(report_date, 'W');
W每月的第1周(1-5),其中第1周从每月的第一天开始
本月7日结束
由于您期望的输出也包括“零”行,并且假设您希望此报告也能跨多个月工作:
WITH sample_data AS
(SELECT DATE '2014-11-01' AS report_date, 23 AS vol FROM DUAL
UNION ALL SELECT DATE '2014-11-03', 34 FROM DUAL
UNION ALL SELECT DATE '2014-11-16', 56 FROM DUAL
UNION ALL SELECT DATE '2014-11-30', 44 FROM DUAL)
,weeks AS
(SELECT report_month
,TO_CHAR(ROWNUM) AS week_no
FROM (SELECT DISTINCT
TRUNC(report_date,'MM') AS report_month
FROM sample_data)
CONNECT BY LEVEL <= TO_NUMBER(TO_CHAR(LAST_DAY(report_month),'W')))
SELECT TO_CHAR(weeks.report_month,'Month') AS "Month"
,weeks.week_no AS "Week no"
,NVL(sum(sample_data.vol),0) AS "Vol"
FROM weeks
LEFT JOIN sample_data
ON weeks.report_month = TRUNC(report_date,'MM')
AND weeks.week_no = to_char(report_date,'W')
GROUP BY weeks.report_month, weeks.week_no ORDER BY 1,2;
几乎是:他想在空的几周里得到0
Month Week no Vol
======== ======= ===
November 1 57
November 2 0
November 3 56
November 4 0
November 5 44