Oracle SQL日期列计数

我只想计算表中重复的dae列。我的桌子是这样的：

访问：

ID_VISIT FK_PATIENT DATEA
0        1          20160425
1        2          20160425
2        3          20160426

我试过这些：

SELECT VISIT.DATEA, COUNT(VISIT.DATEA) as numberOfDate FROM VISIT
SELECT VISIT.DATEA, COUNT(VISIT.DATEA) as numberOfDate FROM VISIT GROUP BY numberOfDate

但我得到的只是这样：

DATEA    NUMBEROFDATE
20160502 1
20160430 1
20160503 1
20160501 1
20160429 1
20160425 1
20160425 1
20160425 1
20160428 1
20160504 1

但我想变成这样

DATEA    NUMBEROFDATE
20160502 1
20160430 1
20160503 1
20160501 1
20160429 1
20160425 3
20160428 1
20160504 1

---

按要唯一的列分组。然后对每个组应用聚合函数，如

count（）

SELECT DATEA, COUNT(DATEA) as numberOfDate 
FROM VISIT 
GROUP BY DATEA

---

按要唯一的列分组。然后对每个组应用聚合函数，如

count（）

SELECT DATEA, COUNT(DATEA) as numberOfDate 
FROM VISIT 
GROUP BY DATEA