Oracle refcursor的SQL语句错误无效

我试图得到基本陈述的结果。SQL语句的工作没有任何问题。但是，为了打印结果，我想使用refcursor。我得到以下错误：

ORA-00900:无效的SQL语句 ORA-01008：并非所有变量都已绑定 ORA-00900:无效的SQL语句

VARIABLE reader refcursor;
DECLARE
  line varchar2(32767);
BEGIN
  line := 'SELECT role_id,';
  FOR n IN (SELECT name
              FROM (SELECT competence.skill_role.role_id,
                           competence.skill_label.name,
                           competence.skill_role.target_value
                      FROM competence.skill_role,
                           competence.skill_label
                     WHERE competence.skill_label.skill_id =
                           competence.skill_role.skill_id
                       AND competence.skill_label.language_id = 1)
                       matrix_result ) LOOP
    line := line || '(decode(name,''' || n.name ||
            ''',target_value)) "' || n.name || '",';
  END LOOP;
  line := RTRIM(line, ',') ||
    ' FROM (SELECT competence.skill_role.role_id,
                   competence.skill_label.name,
                   competence.skill_role.target_value
              FROM competence.skill_role, competence.skill_label
             WHERE competence.skill_label.skill_id =
                   competence.skill_role.skill_id
               AND competence.skill_label.language_id = 1) matrix_result';
--dbms_output.put_line(line);
--execute immediate line;
 OPEN :reader FOR line;
END;
/
PRINT :reader;

表数据

CREATE TABLE competence.skill_role
  (skill_id  NUMBER,
   role_id NUMBER,
   target_value NUMBER)
/
INSERT ALL 
INTO competence.skill_role VALUES (3432030, 1421866, 2)
INTO competence.skill_role VALUES (3434962, 1421866, 2)
INTO competence.skill_role VALUES (3488025, 3488804, 4)


SELECT * FROM competence.skill_role

SKILL_ID ROLE_ID     target_value
---------- -------   -----------
3432030 1421866       2
3434962 1421866       2
3488025 3488804       4


CREATE TABLE competence.skill_label
  (skill_id  NUMBER,
   name vchar2 (30))
/
INSERT ALL 
INTO competence.skill_label VALUES (3432030, 'Alueen projektipätevyys')
INTO competence.skill_label VALUES (3434962, 'Moottorin koekäyttö')
INTO competence.skill_label VALUES (3488025, 'Etähallintajärjestelmät')


SELECT * FROM arc_competence.skill_label

SKILL_ID NAME
---------- -------
3432030, Alueen projektipätevyys
3434962, Moottorin koekäyttö
3488025, Etähallintajärjestelmät

我想从第一个查询得到以下结果。从您的答案（如果我理解正确的话）来看，似乎我需要手动运行结果查询来获得答案。我希望在不运行结果查询的情况下得到结果：-）我目前没有访问客户机的权限，但我现在要去那里

ROLE_ID     Alueen projektipätevyys  Moottorin koekäyttö    Etähallintajärjestelmät          
1421866          2                      2
3488804                                                            4       

---

如果我纠正你的代码，让它编译

• 您的

  INSERT ALL

  语句缺少

  SELECT

• skill\u标签中的
  name
  列定义为
  vchar2（30）
  而不是
  varchar2（30）

• 匿名块引用DDL不包含的列

  language\u id

代码运行时没有错误。如果唯一的问题是要将前两行合并为一行，则只需将

MAX

添加到除

ROLE\u ID

之外的所有列中，并将

groupby ROLE\u ID

添加到查询中

SQL> ed
Wrote file afiedt.buf

  1  CREATE TABLE skill_role
  2    (skill_id  NUMBER,
  3     role_id NUMBER,
  4*    target_value NUMBER)
SQL> /

Table created.

SQL> ed
Wrote file afiedt.buf

  1  INSERT ALL
  2  INTO skill_role VALUES (3432030, 1421866, 2)
  3  INTO skill_role VALUES (3434962, 1421866, 2)
  4  INTO skill_role VALUES (3488025, 3488804, 4)
  5* select * from dual
SQL> /

3 rows created.


SQL> ed
Wrote file afiedt.buf

  1  CREATE TABLE skill_label
  2    (skill_id  NUMBER,
  3*    name varchar2 (30))
SQL> /

Table created.

SQL> ed
Wrote file afiedt.buf

  1  INSERT ALL
  2  INTO skill_label VALUES (3432030, 'Alueen projektipΣtevyys')
  3  INTO skill_label VALUES (3434962, 'Moottorin koekΣytt÷')
  4  INTO skill_label VALUES (3488025, 'EtΣhallintajΣrjestelmΣt')
  5* select * from dual
SQL> /

3 rows created.

SQL> commit;

Commit complete.

SQL> variable reader refcursor;

SQL> ed
Wrote file afiedt.buf

  1  DECLARE
  2    line varchar2(32767);
  3  BEGIN
  4    line := 'SELECT role_id,';
  5    FOR n IN (SELECT name
  6                FROM (SELECT skill_role.role_id,
  7                             skill_label.name,
  8                             skill_role.target_value
  9                        FROM skill_role,
 10                             skill_label
 11                       WHERE skill_label.skill_id =
 12                             skill_role.skill_id
 13                         )
 14                         matrix_result ) LOOP
 15      line := line || 'max(decode(name,''' || n.name ||
 16              ''',target_value)) "' || n.name || '",';
 17    END LOOP;
 18    line := RTRIM(line, ',') ||
 19      ' FROM (SELECT skill_role.role_id,
 20                     skill_label.name,
 21                     skill_role.target_value
 22                FROM skill_role, skill_label
 23               WHERE skill_label.skill_id =
 24                     skill_role.skill_id
 25                 ) matrix_result ' ||
 26       ' GROUP BY role_id' ;
 27    dbms_output.put_line(line);
 28    --execute immediate line;
 29    OPEN :reader FOR line;
 30* END;
 31  /

PL/SQL procedure successfully completed.

SQL> print reader

   ROLE_ID Alueen projektipΣtevyys Moottorin koekΣytt÷ EtΣhallintajΣrjestelmΣt
---------- ----------------------- ------------------- -----------------------
   1421866                       2                   2
   3488804                                                                   4

---

如果取消对

dbms\u输出的注释。在
OPEN
之前放置\u line

调用，它显示的SQL语句是什么？我得到了SQL查询的结果（这本身就是用于动态数据透视的有效SQL查询），那么我会感到困惑。如果

line

是一个有效的SQL查询，那么代码将成功运行（如下所示）。如果您遇到错误，这意味着您生成的SQL语句无效，或者您没有提到问题的更多方面。谢谢..我刚刚编辑了我的原始问题，以便显示所需的结果。（顺便问一下，我如何在我的回答中添加代码，因为现在我编辑了我的原始问题以添加行以获得所需的结果。嗯……代码中声明的“reader”在哪里？（来自第28行）@Jaanna-我对

阅读器的声明与你的声明相同。只是我忘记了在复制和粘贴中包含第一行。我修复了这一点，并调整了代码以返回你想要的结果。