Oracle11g 透视还是取消透视查询结果？

我不熟悉Oracle中令人困惑的pivot和unpivot操作符。有人能帮我分析一下这样一个查询的结果吗

SELECT * FROM
(
    SELECT
    ROUND(((SELECT COUNT(*) FROM TABLE_X WHERE X = 1) / (SELECT (COUNT(*)) FROM TABLE_X) * 100))AS X_FIELD,
    ROUND(((SELECT COUNT(*) FROM TABLE_Y WHERE Y = 1) / (SELECT (COUNT(*)) FROM TABLE_Y) * 100))AS Y_FIELD FROM DUAL

);

结果如下：

X_FIELD        Y_FIELD
----------     ----------
37             26

FIELDS         PERCENTAGE
----------     ----------
X_FIELD        37 
Y_FIELD        26

我需要这样的东西：

X_FIELD        Y_FIELD
----------     ----------
37             26

FIELDS         PERCENTAGE
----------     ----------
X_FIELD        37 
Y_FIELD        26

请指导我如何做到这一点。

尝试以下方法：

WITH temp_result AS
  (SELECT ROUND((
    (SELECT COUNT(*) FROM TABLE_X WHERE X = 1) /(SELECT (COUNT(*)) FROM TABLE_X) * 100))AS X_FIELD,
    ROUND(((SELECT COUNT(*) FROM TABLE_Y WHERE Y = 1) /(SELECT (COUNT(*)) FROM TABLE_Y) * 100))AS Y_FIELD
  FROM DUAL
  )
SELECT *
FROM temp_result UNPIVOT INCLUDE NULLS ( VALUE FOR COL IN (X_FIELD,Y_FIELD));

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很高兴它起作用了。您可以接受已解决的答案，以便将来搜索类似问题的用户可以在不阅读注释的情况下使用它。