Osgi 无法以编程方式启动捆绑包
注意:在我的例子中,如果有必要的话,我正在使用Osgi 无法以编程方式启动捆绑包,osgi,osgi-bundle,embedded-osgi,Osgi,Osgi Bundle,Embedded Osgi,注意:在我的例子中,如果有必要的话,我正在使用apachefelix实现 我已经编写了一个包,我正在使用它作为测试。这是一个非常简单的“Hello World”捆绑包,在启动/停止时只需将消息打印到标准输出即可: public class Activator implements BundleActivator { @Override public void start(BundleContext context) throws Exception { Syst
apachefelix
实现
我已经编写了一个包,我正在使用它作为测试。这是一个非常简单的“Hello World”捆绑包,在启动/停止时只需将消息打印到标准输出即可:
public class Activator implements BundleActivator {
@Override
public void start(BundleContext context) throws Exception {
System.out.println("Hello, World.");
}
@Override
public void stop(BundleContext context) throws Exception {
System.out.println("Goodbye, World.");
}
}
还有一个MANIFEST
文件,当我通过apachefelix
console从标准发行版()部署上述包时,该包启动并打印出消息,因此发布该文件是毫无意义的
我要做的下一步是使用编程方法部署相同的包。不幸的是,这对我不起作用。我的代码如下所示:
public static void main(String[] args) throws Exception {
FrameworkFactory frameworkFactory = getFrameworkFactory();
Framework framework = frameworkFactory.newFramework(null);
System.out.println("BundleID = " + framework.getBundleId());
System.out.println("State = " + getState(framework.getState()));
framework.init();
System.out.println("BundleID = " + framework.getBundleId());
System.out.println("State = " + getState(framework.getState()));
BundleContext bundleContext = framework.getBundleContext();
bundleContext.addBundleListener((event) -> {
System.out.println("Bundle Changed Event");
});
bundleContext.addFrameworkListener((event) -> {
System.out.println("Framework Event");
});
bundleContext.addServiceListener((event) -> {
System.out.println("Service Changed Event");
});
Bundle bundle = bundleContext.installBundle("file://<absolute-path-to-bundle-jar-same-as-above");
System.out.println("BundleID = " + bundle.getBundleId());
System.out.println("State = " + getState(bundle.getState()));
bundle.start();
System.out.println("BundleID = " + bundle.getBundleId());
System.out.println("State = " + getState(bundle.getState()));
}
private static FrameworkFactory getFrameworkFactory() throws IllegalStateException {
ServiceLoader<FrameworkFactory> loader = ServiceLoader.load(FrameworkFactory.class);
FrameworkFactory factory = null;
for (FrameworkFactory iterator : loader) {
if (factory != null) {
throw new IllegalStateException("Ambiguous SPI implementations.");
}
factory = iterator;
}
return factory;
}
private static String getState(int state) {
switch (state) {
case Bundle.UNINSTALLED:
return "UNINSTALLED";
case Bundle.INSTALLED:
return "INSTALLED";
case Bundle.RESOLVED:
return "RESOLVED";
case Bundle.STARTING:
return "STARTING";
case Bundle.STOPPING:
return "STOPPING";
case Bundle.ACTIVE:
return "ACTIVE";
default:
throw new IllegalStateException("Unknown state");
}
}
据我所知,bundle已安装,但最后4行表明由于某种原因,bundle.start()
被忽略
您能告诉我,我缺少了什么来完成这项工作吗?经过一个小时的调试和更仔细地阅读
javadoc
之后,这种情况发生了,因为框架只是初始化了,而没有启动。为了使示例有效,您只需在framework.init()
之后添加framework.start()
(或者只要调用framwork.start()
,如果需要,它会调用framework.init()
)
我留下这些信息是因为有一些令人困惑的事情:
apachefelix
定制机制,使得它无法移植到其他实现中。令人困惑的是,如果要创建可移植解决方案,应该使用init()
和getBundleContext()
。以下引用整条注释:init()
,并直接使用getBundleContext()
。否则,方法将非常相似
init()
方法不提及初始化与启动框架不同,尽管init(FrameworkListener…
有此类信息BundleID = 0
State = INSTALLED
BundleID = 0
State = STARTING
Bundle Changed Event
BundleID = 1
State = INSTALLED
BundleID = 1
State = INSTALLED