Perl中的RSA密钥

我有简单的RSA编码/解码脚本，例如：

use Crypt::RSA;

my $rsa = new Crypt::RSA;
my($public, $private) = $rsa->keygen( Size => 2048 )
                        or die $rsa->errstr();

my $email = '...';

my $em = $rsa->encrypt( Message => $email, Key => $public  );
my $dm = $rsa->decrypt( Ciphertext => $em, Key => $private );

print "$dm\n";

e => 10001
d => 135b03530e94874283f0f0000ffff0001
n => 24000c6c9620886831124848640044901

但是，我想修改此脚本以使用RSA密钥作为e、d和n值，例如：

use Crypt::RSA;

my $rsa = new Crypt::RSA;
my($public, $private) = $rsa->keygen( Size => 2048 )
                        or die $rsa->errstr();

my $email = '...';

my $em = $rsa->encrypt( Message => $email, Key => $public  );
my $dm = $rsa->decrypt( Ciphertext => $em, Key => $private );

print "$dm\n";

e => 10001
d => 135b03530e94874283f0f0000ffff0001
n => 24000c6c9620886831124848640044901

如何将这三个参数转换为

Crypt:：RSA:：Key

对象，反之亦然

---

或者，我如何将这三个参数与

Crypt:：RSA

一起用于加密和解密？

我建议您检查此模块：，或者检查我如何在github中的存储库中使用它：

通过参数n、e、d创建RSA

use strict;

use Crypt::OpenSSL::Bignum;
use Crypt::OpenSSL::Random;
use Crypt::OpenSSL::RSA;

my $param_ref = {
    n => 'C8F19E3A7C18A5FE6D1DE07926F4E6403EA6558EE4892D29155F2C52678E210FE5D61DBC9EC77F2DD39FC8D9F2717F23629B7E18BDB38AADF9FC5BF1CA968C67F4BF0F2D6657E1374A845048B6CDCB2B8B2B3F31BF7F134A11B9A063EB7C326B27C0027955637E6089293F5F4CD40F5B91142BBA61B8E473A8D14B447896B5FD',
    e => '010001',
    d => '574C612997703DED630A6FD3329182D6B6611D1A8F3EE957C7E9292043CD03A01C82013948E1F2E6BDE1D5289AA3A450832E7A81D528833F4233D8DE1ADD7CF1878CBACDE64DE4364F8B73093753D6E322732EAEC942281CE4AF55D212E77EC4A108708864D3F86A67C63FBE8206A543A42ABF45E56C1E41A2F2BA0CCC1C8001',
};

my $n = Crypt::OpenSSL::Bignum->new_from_hex($param_ref->{n});
my $e = Crypt::OpenSSL::Bignum->new_from_hex($param_ref->{e});
my $d = Crypt::OpenSSL::Bignum->new_from_hex($param_ref->{d});

my $rsa = Crypt::OpenSSL::RSA->new_key_from_parameters($n, $e, $d);

printf "private key is: %s\n", $rsa->get_private_key_string();
printf "public key (in PKCS1 format) is: %s\n", $rsa->get_public_key_string();

从RSA对象获取关键参数

use strict;

use Crypt::OpenSSL::Bignum;
use Crypt::OpenSSL::Random;
use Crypt::OpenSSL::RSA;

my $rsa = Crypt::OpenSSL::RSA->generate_key(2048);
my ($n, $e, $d, $p, $q) = $rsa->get_key_parameters();

printf "private key is: %s\n", $rsa->get_private_key_string();
printf "public key (in PKCS1 format) is: %s\n", $rsa->get_public_key_string();

---

谢谢是否可以使用

Crypt:：OpneSSL:：RSA

对具有n+e和d+e值的消息进行加密/解密？我需要允许public对消息进行解密，加密使其成为私有的，所以我不能从

$rsa->get_private_key_string

分发私钥。请给出建议。是的，对于用公钥加密的消息，这就足够了（n+e），对于用私钥解密的消息，这就足够了（n+e+d）p+q-帮助快速计算。请再次阅读我的评论-相反：我需要用公钥解密，用私钥加密。。。可能吗@Ωmega，是的，您可以使用名为

private\u encrypt

的

Crypt:：OpenSSL:：RSA