Php 在公共函数中插入查询

我想在单类函数中编写两个insert查询。任何人都知道，请帮助我。这是我的密码：

public function insertlocation($data) {
    $this->db->insert ( 'locations', array (
            'subscriber_id' => Session::get ( 'subId' ),
            'location_name' => $data ['location_name'],
            'location_ip' => $data ['location_ip'],
            'working_hours_start' => date ( 'H:i:s', strtotime ( $data ['w_time_start'] ) ),
            'working_hours_end' => date ( 'H:i:s', strtotime ( $data ['w_time_end'] ) ),
            'time_zone' => $data ['time_zone'],
            'ip_lock' => $data ['select_ip_lock'],
            'time_lock' => $data ['select_time_lock'],
            'created' => date ( 'Y-m-d H:i:s' ),
            'status' => $data ['status'],
            'currency_id' => $data ['currency'],
            'monthly_target' => $data ['target'] 
    ) );
    return $this->db->lastInsertId ();

    $this->db->insert ( 'year_target', array (
            'location_ip' => $data ['location_ip'],
            'year' => $data ['year'],
            'monthly_target' => $data ['target'] 
    )
     );
}

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移除函数中间的返回，并在结束时返回插入ID（如果需要的话）。

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我试过这个。但是这些值只插入位置表，而不插入年份目标表。如果您切换订单或根本不在

位置中插入任何内容，该怎么办？请尝试提取一个最小的示例，我很确定您没有讲述整个故事，这是理解发生了什么的关键点。我需要在两个表中插入值。年份列应插入年份\目标表，而不是位置表。这就是我创建year_目标表的原因@Ulricheckhardt请学习发布指南，特别是关于创建最小示例的部分。谢谢！！我发现了这个问题。
public function insertlocation($data) {
    $this->db->insert ( 'locations', array (
            'subscriber_id' => Session::get ( 'subId' ),
            'location_name' => $data ['location_name'],
            'location_ip' => $data ['location_ip'],
            'working_hours_start' => date ( 'H:i:s', strtotime ( $data ['w_time_start'] ) ),
            'working_hours_end' => date ( 'H:i:s', strtotime ( $data ['w_time_end'] ) ),
            'time_zone' => $data ['time_zone'],
            'ip_lock' => $data ['select_ip_lock'],
            'time_lock' => $data ['select_time_lock'],
            'created' => date ( 'Y-m-d H:i:s' ),
            'status' => $data ['status'],
            'currency_id' => $data ['currency'],
            'monthly_target' => $data ['target'] 
    ) );

    $return_value[] = $this->db->lastInsertId ();

    $this->db->insert ( 'year_target', array (
            'location_ip' => $data ['location_ip'],
            'year' => $data ['year'],
            'monthly_target' => $data ['target'] 
    ));

    $return_value[] = $this->db->lastInsertId ();

    return $return_value;
}