显示使用php curl检索的json数据时出现问题_Php_Json_Curl

显示使用php curl检索的json数据时出现问题

php json curl

显示使用php curl检索的json数据时出现问题,php,json,curl,Php,Json,Curl,首先，谢谢你的阅读。这是我的密码使用url在浏览器中查看我的json数据时的外观 { "$totalResults": 1500, "$startIndex": 1, "$itemsPerPage": 3, "$resources": [ { "$uuid": "5e7b9312-52e5-4fe1-b3e4-633ca04c9764", "$httpStatus": "OK", "$descriptor": "", "n

首先，谢谢你的阅读。这是我的密码

使用url在浏览器中查看我的json数据时的外观

{
  "$totalResults": 1500,
  "$startIndex": 1,
  "$itemsPerPage": 3,
  "$resources": [
    {
      "$uuid": "5e7b9312-52e5-4fe1-b3e4-633ca04c9764",
      "$httpStatus": "OK",
      "$descriptor": "",
      "name": "Heinz Tomato Sauce  Sachets Qty 200"
    },
    {
      "$uuid": "1a0f9dca-c417-4cff-94d2-99d16438723f",
      "$httpStatus": "OK",
      "$descriptor": "",
      "name": "Heinz Brown Sauce Sachet Qty 200"
    },
    {
      "$uuid": "126fdb17-81ce-41b4-bdba-91d0a170262a",
      "$httpStatus": "OK",
      "$descriptor": "",
      "name": "Heinz English Mustard  Sachets Qty 300"
    }
  ]
}

test2.php

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&format=json';

//SAGE USERNAME & PASSWORD
$username = 'test';
$password = 'test';


    //initiaize
$ch = curl_init();

    //set options       
curl_setopt($ch, CURLOPT_URL,$url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);        

    //execute 
$result = curl_exec($ch);

    //close curl session / free resources
curl_close($ch);

$json = json_decode($result);

foreach ($json->{'$resources'} as $mydata) {
    echo $mydata->name;
};

?>

我不确定出了什么问题，如果我从一个文件中获得相同的数据，但如果我从rest服务器检索数据，这是不可行的，如果有人能告诉我一些情况，我将非常感激PHP json_decode函数返回一个数组而不是一个对象，所以不要使用

foreach ($json->{'$resources'} as $mydata) {
    echo $mydata->name;
};

你应该使用

foreach ($json['$resources'] as $mydata) {
    echo $mydata['name'];
};

更新

您的test2.php应该如下所示：

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&format=json';

//SAGE USERNAME & PASSWORD
$username = 'test';
$password = 'test';


//initiaize
$ch = curl_init();

//set options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

//execute
$result = curl_exec($ch);

//close curl session / free resources
curl_close($ch);

$json = json_decode($result);
$json = (array)$json;

foreach ($json['$resources'] as $mydata) {
    echo $mydata->name . "<br>";
};

在您的代码中，主要的问题是JSON属性$resources的命名：它被命名为PHP变量，这导致了问题

将解码后的变量转换为数组可以解决问题，因为关联数组键是字符串。

PHP json\u decode函数返回数组而不是对象，因此不使用

foreach ($json->{'$resources'} as $mydata) {
    echo $mydata->name;
};

你应该使用

foreach ($json['$resources'] as $mydata) {
    echo $mydata['name'];
};

更新

您的test2.php应该如下所示：

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&format=json';

//SAGE USERNAME & PASSWORD
$username = 'test';
$password = 'test';


//initiaize
$ch = curl_init();

//set options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

//execute
$result = curl_exec($ch);

//close curl session / free resources
curl_close($ch);

$json = json_decode($result);
$json = (array)$json;

foreach ($json['$resources'] as $mydata) {
    echo $mydata->name . "<br>";
};

在您的代码中，主要的问题是JSON属性$resources的命名：它被命名为PHP变量，这导致了问题

将解码的变量转换为数组可以解决问题，因为关联数组键是字符串。

Ajking11为foreach提供的参数无效的原因是$json variable被覆盖，没有数据。请尝试类似的操作

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3';

//SAGE USERNAME & PASSWORD
$username = 'test';
$password = 'test';


//initiaize
$ch = curl_init();

//set options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

//execute
$result = curl_exec($ch);

//close curl session / free resources
curl_close($ch);
$xml = simplexml_load_string($result);
$data = json_encode($xml);
$arr = json_decode($data,TRUE);


foreach ($arr['entry'] as $k=>$v){
    echo $v; // etc.
}

请注意，我已经删除了&format=json，并在稍后进行了编码。希望这有助于让我了解您的进展情况。11您获取foreach提供的无效参数的原因是$json VARIABLE被覆盖，没有数据。请尝试类似的操作

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3';

//SAGE USERNAME & PASSWORD
$username = 'test';
$password = 'test';


//initiaize
$ch = curl_init();

//set options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

//execute
$result = curl_exec($ch);

//close curl session / free resources
curl_close($ch);
$xml = simplexml_load_string($result);
$data = json_encode($xml);
$arr = json_decode($data,TRUE);


foreach ($arr['entry'] as $k=>$v){
    echo $v; // etc.
}

请注意，我已经删除了&format=json并在以后进行了编码。希望这有助于我了解您的进展情况。您可能希望使用此代码并根据需要对其进行优化

<?php
    // SAGE URL
        //$url = 'http://computer_2:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&select=name&count=10&format=json';
        $url ='http://localhost:5493/sdata/accounts50/GCRM/-/tradingAccounts?select=name&count=10';
        //SAGE USERNAME & PASSWORD
        $username = 'MANAGER';
        $password = '';

        //initiaize
        $ch = curl_init();

        //set options
        curl_setopt($ch, CURLOPT_URL, $url);
        curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
        curl_setopt($ch, CURLOPT_HTTPGET, true);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_HEADER, 0);

        //execute
        $result = curl_exec($ch);

        //close curl session / free resources
        curl_close($ch);
        $xml = simplexml_load_string($result);



foreach($xml->xpath("//sdata:payload") as $entry) {
    // xpath here must be from payload to tradingAccount
    $content = $entry->xpath("./crm:tradingAccount");
    foreach($content as $c) {
       // Make set of children with prefix crm
       $nodes = $c->children('crm', true); 
       echo $nodes->reference . " | " . $nodes->name . " / " . $nodes->openedDate . "<br />\n";

    }
}

感谢PHPhil和splash58在名称空间问题上提供的帮助

您可能希望使用此代码并根据需要对其进行优化

<?php
    // SAGE URL
        //$url = 'http://computer_2:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&select=name&count=10&format=json';
        $url ='http://localhost:5493/sdata/accounts50/GCRM/-/tradingAccounts?select=name&count=10';
        //SAGE USERNAME & PASSWORD
        $username = 'MANAGER';
        $password = '';

        //initiaize
        $ch = curl_init();

        //set options
        curl_setopt($ch, CURLOPT_URL, $url);
        curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
        curl_setopt($ch, CURLOPT_HTTPGET, true);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
        curl_setopt($ch, CURLOPT_HEADER, 0);

        //execute
        $result = curl_exec($ch);

        //close curl session / free resources
        curl_close($ch);
        $xml = simplexml_load_string($result);



foreach($xml->xpath("//sdata:payload") as $entry) {
    // xpath here must be from payload to tradingAccount
    $content = $entry->xpath("./crm:tradingAccount");
    foreach($content as $c) {
       // Make set of children with prefix crm
       $nodes = $c->children('crm', true); 
       echo $nodes->reference . " | " . $nodes->name . " / " . $nodes->openedDate . "<br />\n";

    }
}

感谢PHPhil和splash58在名称空间问题上的帮助，因为巧妙的dodger说json是这里的问题，我将如何解决它

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&format=json';

//SAGE USERNAME & PASSWORD
$username = 'MANAGER';
$password = '';


//initiaize
$ch = curl_init();

//set options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

//execute
$result = curl_exec($ch);

//close curl session / free resources
curl_close($ch);

// doing a substring as there are 3 weird characters being passed back from IIS in front of the string
$json = json_decode(substr($result, 3, strlen($result)), true);


    foreach ($json['$resources'] as $mydata) {
        echo $mydata['name'] . "<br>";
    }

正如Artful_dodger所说，json是这里的问题，我将如何解决它

<?php

// SAGE URL
$url = 'http://localhost:5493/sdata/accounts50/GCRM/-/commodities?select=name&count=3&format=json';

//SAGE USERNAME & PASSWORD
$username = 'MANAGER';
$password = '';


//initiaize
$ch = curl_init();

//set options
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($ch, CURLOPT_HTTPGET, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);

//execute
$result = curl_exec($ch);

//close curl session / free resources
curl_close($ch);

// doing a substring as there are 3 weird characters being passed back from IIS in front of the string
$json = json_decode(substr($result, 3, strlen($result)), true);


    foreach ($json['$resources'] as $mydata) {
        echo $mydata['name'] . "<br>";
    }

我真的很抱歉再也没有回复你。因此，当您从sage服务获取数据时，它会以utf 8 bom的形式返回给您

因此，在显示任何内容之前，我需要通过清除数组中的前三个字符来删除格式。使用substr函数

$json_data = substr($json_data, 3);

谢谢大家帮我解决这个问题。

我真的很抱歉再也没有给你们回复。因此，当您从sage服务获取数据时，它会以utf 8 bom的形式返回给您

因此，在显示任何内容之前，我需要通过清除数组中的前三个字符来删除格式。使用substr函数

$json_data = substr($json_data, 3);

感谢大家帮助解决这个问题。

检查$json和$result变量中的内容。不确定要使用什么，我做了一个版本转储isset；和&results里面有东西，但是$json不知道是怎么回事。检查$json和$result变量中的内容。不确定要使用什么，我做了一个版本转储isset；and&results中有内容，但$json不知道是怎么回事。更改foreach返回：警告：第29行的C:\xampp\htdocs\Sage json\test2.php中为foreach提供的参数无效。您是否能够解析导致上述响应的json文件开头的无效字符更改foreach返回：警告：第29行的C:\xampp\htdocs\Sage Json\test2.php中为foreach提供的参数无效。您是否能够解析导致上述响应的Json文件开头的无效字符？我已经对此做了更多的研究，$Json\u decode的$result部分似乎不是有效的Json代码，因此返回nullI对此做了更多的研究，似乎$json_decode的$result部分不是有效的json代码，因此返回null