Php 迭代按某个字段排序的原则集合
我需要这样的东西:Php 迭代按某个字段排序的原则集合,php,sorting,collections,doctrine,doctrine-1.2,Php,Sorting,Collections,Doctrine,Doctrine 1.2,我需要这样的东西: $products = Products::getTable()->find(274); foreach ($products->Categories->orderBy('title') as $category) { echo "{$category->title}<br />"; } class ExampleClass { public
$products = Products::getTable()->find(274);
foreach ($products->Categories->orderBy('title') as $category)
{
echo "{$category->title}<br />";
}
class ExampleClass
{
public static function sortByAge( $a , $b )
{
$age_a = $a->age;
$age_b = $b->age;
return $age_a == $age_b ? 0 : $age_a > $age_b ? 1 : - 1;
}
public function sortExample()
{
$users = User::getTable()->findAll();
$users ->sortBy('ExampleClass::sortByAge');
echo "Oldest User:";
var_dump ( $users->end() );
}
}
$products=products::getTable()->find(274);
foreach($products->CATEGORES->orderBy('title')作为$category)
{
回声“{$category->title}
”;
}
我知道这是不可能的,但是。。。我如何在不创建条令查询的情况下执行类似操作
谢谢。我刚才也在看同样的问题。您需要将集合转换为数组:
$someDbObject = Doctrine_Query::create()...;
$children = $someDbObject->Children;
$children = $children->getData(); // convert from Doctrine_Collection to array
然后,您可以创建自定义排序函数并调用它:
// sort children
usort($children, array(__CLASS__, 'compareChildren')); // fixed __CLASS__
其中compareChildren看起来像:
private static function compareChildren($a, $b) {
// in this case "label" is the name of the database column
return strcmp($a->label, $b->label);
}
您还可以执行以下操作:
$this->hasMany('Category as Categories', array(...
'orderBy' => 'title ASC'));
在架构文件中,它看起来像:
Relations:
Categories:
class: Category
....
orderBy: title ASC
您可以向Colletion.php添加排序函数:
public function sortBy( $sortFunction )
{
usort($this->data, $sortFunction);
}
按年龄对用户集合进行排序如下所示:
$products = Products::getTable()->find(274);
foreach ($products->Categories->orderBy('title') as $category)
{
echo "{$category->title}<br />";
}
class ExampleClass
{
public static function sortByAge( $a , $b )
{
$age_a = $a->age;
$age_b = $b->age;
return $age_a == $age_b ? 0 : $age_a > $age_b ? 1 : - 1;
}
public function sortExample()
{
$users = User::getTable()->findAll();
$users ->sortBy('ExampleClass::sortByAge');
echo "Oldest User:";
var_dump ( $users->end() );
}
}
您可以使用集合迭代器:
$collection=Table::getInstance()->findAll();
$iter=$collection->getIterator();
$iter->uasort(函数($a,$b){
$name_a=(int)$a->getName();
$name_b=(int)$b->getName();
返回$name\u a==$name\u b?0:$name\u a>$name\u b?1:-1;
});
foreach($iter作为$element){
//…现在您可以迭代已排序的集合
}
如果要使用u_toString方法对集合进行排序,则会更容易:
foreach($collection->getIterator()->asort()作为$element){/*…*/}
如果排序是“永久性”的,那么使用这种方法比使用Chris William的方法要好得多。缺点是永久性。向此关系的每个查询中添加orderBy将影响性能。或者通过@orderBy
注释:您的解决方案只有在我将其更改为:usort($children,array(u__________________;尝试使用$collection->getIterator()->asort()
,但它只返回bool。对不起,我忘了它是如何工作的。你说得对,成功时返回true,失败时返回false。这是一个很好的设计。如果在迭代之前调用asort,您将能够遍历排序列表。