Android应用程序连接php文件和条件简单

我需要我的android应用程序连接到一个PHP文件（只需在表上进行选择并以JSON格式显示结果），我如何将我的应用程序连接到PHP文件并生成一个条件？例如：

JSON:

条件：

if (ResultPHP==hola){
 //se encontró correctamente 'hola'
}else{
 //no se encontró 'hola'
}

目前，我的连接代码是：

 public class QRpost {

 public static void postData() {
 // Create a new HttpClient and Post Header
 HttpClient httpclient = new DefaultHttpClient();
 HttpPost httppost = new HttpPost("qr.php");
 try {
   // Execute HTTP Post Request
   HttpResponse response = httpclient.execute(httppost);
   HttpEntity entity = response.getEntity();
   InputStream webs = entity.getContent();
   try{
    BufferedReader reader = new BufferedReader(new InputStreamReader(webs,"iso-8859-1"),8);
    webs.close();
   }catch(Exception e){
    Log.e("log_tag", "Error al convertir el resultado");
   }
  } catch (ClientProtocolException e) {
   // TODO Auto-generated catch block
   } catch (IOException e) {
   // TODO Auto-generated catch block
  }
  }
 }

---

有人能帮我吗？对不起我的英语：（

在创建

BufferedReader

之后，您需要将每一行读入

StringBuilder

        BufferedReader reader = new BufferedReader(new InputStreamReader(webs,"iso-8859-1"),8);

        StringBuilder builder = new StringBuilder();
        String line = null;

        while ((line = reader.readLine()) != null) {

            builder.append(line);
        }

        webs.close();

        String json = builder.toString();

json

变量将包含所有json作为

String

。然后需要在该字符串上使用json解析器从json中获取所需的变量。有关如何解析字符串，请参阅

JSONObject

和

JSONArray

        BufferedReader reader = new BufferedReader(new InputStreamReader(webs,"iso-8859-1"),8);

        StringBuilder builder = new StringBuilder();
        String line = null;

        while ((line = reader.readLine()) != null) {

            builder.append(line);
        }

        webs.close();

        String json = builder.toString();