Warning: file_get_contents(/data/phpspider/zhask/data//catemap/7/css/33.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
如何使用CSS在PHP中编辑div_Php_Css - Fatal编程技术网

如何使用CSS在PHP中编辑div

如何使用CSS在PHP中编辑div,php,css,Php,Css,如何使用CSS编辑这三个div,使结果成为一个表(但更好。我使用Microsoft Word创建了该表) 创建人 接触 描述 我想你在问这个。试试上面的代码。表格不仅仅是使用CSS自动创建的。将您的div改为tables。您能接受这个答案吗@lybinpeterbabuy您似乎缺少一些。 <?php $servername = "localhost"; $username = "root"; $password = "";

如何使用CSS编辑这三个div,使结果成为一个表(但更好。我使用Microsoft Word创建了该表)



创建人
接触
描述

我想你在问这个。试试上面的代码。

表格不仅仅是使用CSS自动创建的。将您的div改为tables。您能接受这个答案吗@lybinpeterbabuy您似乎缺少一些
<?php
        $servername = "localhost";
        $username = "root";
        $password = "";
        $dbname = "hangman";

        try {
            $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
            $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $stmt = $conn->prepare("SELECT * FROM `credits`");
            $stmt->execute();

            $result = $stmt->fetch(PDO::FETCH_ASSOC);
            echo "<div>Created By: ".$result["author_name"]."<br></div>";
            echo "<div>Contact: ".$result["author_email"]."<br></div>";
            echo "<div>Description: ".$result["description"]."</div>";
        }
        catch(PDOException $e) {
            echo "Error: " . $e->getMessage();
        }
        $conn = null;
    ?>
    <?php
        $servername = "localhost";
        $username = "root";
        $password = "";
        $dbname = "hangman";
    ?>
      <table>
          <td>Created By</td>
          <td>Contact</td>
          <td>Description</td>
<?php
        try {
            $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
            $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $stmt = $conn->prepare("SELECT * FROM `credits`");
            $stmt->execute();

            $result = $stmt->fetch(PDO::FETCH_ASSOC);
            echo "<tr>";
            echo "<td>".$result["author_name"]."</td>";
            echo "<td>".$result["author_email"]."</td>";
            echo "<td>".$result["description"]."</td>";
            echo "</tr>";
        }
        catch(PDOException $e) {
            echo "Error: " . $e->getMessage();
        }
        $conn = null;
    ?>
</table>