Php 困难的SQL查询语法
大家好这里是我的MySQL查询哪一个正在获取数据Php 困难的SQL查询语法,php,mysql,sql,pdo,Php,Mysql,Sql,Pdo,大家好这里是我的MySQL查询哪一个正在获取数据 $videofetch = $conn->prepare("select * from user_followers as uf join videos as v on uf.followed_id = v.publisher_id where uf.follower_id = ? order by video_id desc limit 5"); $videofetch->execute(array(@$_SESSION ["use
$videofetch = $conn->prepare("select * from user_followers as uf join videos as v on uf.followed_id = v.publisher_id where uf.follower_id = ? order by video_id desc limit 5");
$videofetch->execute(array(@$_SESSION ["userid"]));
$vid = $videofetch->fetchALL(PDO::FETCH_ASSOC);
这段代码工作得很好,但是当我试图用AJAX获取更多数据时,我无法编写正确的sql查询语法
<?php
session_start();
if(isset($_POST["id"]) && !empty($_POST["id"])) {
include('connectdb.php');
$lastID = $_POST['id'];
$videofetch = $conn->prepare("select * from user_followers as uf join videos as v on uf.followed_id = v.publisher_id where uf.follower_id = ? order by video_id desc limit 5");
$videofetch->execute(array($_SESSION["userid"]));
$vid = $videofetch->fetchALL(PDO::FETCH_ASSOC);
...
尝试对mysql关键字进行大写。读起来好多了
你已经有了WHERE,所以你只需要把它和And结合起来
SELECT *
FROM user_followers AS uf
JOIN videos AS v ON uf.followed_id = v.publisher_id
WHERE uf.follower_id = ?
AND video_id < ".$lastID."
ORDER BY video_id DESC
LIMIT 5
选择*
来自用户_followers作为uf
在uf.id=v.publisher\u id上以v的身份加入视频
其中uf.follower_id=?
和视频id<“$lastID”
按视频订购\u id DESC
限制5
但是,请使用准备好的语句更改“.$lastID.”。视频为v
=>视频为v
-您可以使用as
作为列别名,而不是表别名。将as从表别名中删除,以便进行视频第一次查询。我只想将添加到视频id
到第二个查询我将尝试感谢您的回复我尝试了两个组合,没有as
,但仍然存在相同的语法错误:)就是这样兄弟这是正确的答案非常感谢,$videofetch=$conn->prepare(“选择*从用户跟随者作为uf加入视频作为uf上的v.followed_id=v.publisher_id,其中uf.follower_id=?和视频_id<”$lastID.“按视频订购_iddesc LIMIT 5”);$videofetch->execute(数组($_会话[“userid”]);