Php 找不到Imagepath的Url

我正在为一个大学项目制作一个食谱网站，并且正在编写一个上传页面，这样人们就可以上传自己的食谱，其中一个选项允许他们上传一张与食谱相关的图片

我已经设法使实际的上传工作，并插入一个imagepath到我的数据库。 当我尝试打印图像时，出现了一个404错误，告诉我找不到图像，尽管我不理解这一点，因为我可以在浏览器中导航到图像

这是上传页面的代码

<?php
require_once ("checklog.php");
require_once ("function.php");
include_once ("home_start_logged.php");
require_once ("db_connect.php");
require_once ("cuisine_dropdown.php");

session_start();

//get form data//
$upload = trim($_POST['Upload']);
$mealname = trim($_POST['mealname']);
$ingredients = trim($_POST['ingredients']);
$hours = trim($_POST['hours']);
$minutes = trim($_POST['minutes']);
$recipe = trim($_POST['recipe']);
$userid = trim($_SESSION['userid']);
$cuisine = trim($_POST['cuisine']);
$meal = trim($_POST['meal']);
$feeds = trim($_POST['feeds']);
$dropoption = trim($_POST['dropoption']);
if(trim($_POST['Submit']) =="Upload"){

        //handle submitted data here
//process details here// 
    if($db_server){
        //clean the input now we have a db connection//
        $mealname = clean_string($db_server, $mealname);
        $ingredients = clean_string($db_server, $ingredients);
        $hour = clean_string($db_server, $hour);
        $minutes = clean_string($db_server, $minutes);
        $recipe = clean_string($db_server, $recipe);
        $ingredients = clean_string($db_server, $ingredients);
        $userid = clean_string($db_server, $userid);
        $cuisine = clean_string($db_server, $cuisine);
        $meal = clean_string($db_server,$meal);
        $feeds = clean_string($db_server,$feeds);
        $dropoption = clean_string($db_server, $dropoption);
        mysqli_select_db($db_server, $db_database) ;

        //check whether the recipe exists//
        $query="SELECT mealname FROM `recipename` WHERE mealname='$mealname'";
        $result = mysqli_query($db_server, $query);
        if ($row = mysqli_fetch_array($result)){
            $message = "Meal already exists. Please try again.";
        }else{                                                      
                                //code to process image here//
                                //put file properties into variable//
                                if($_FILES) {
                                $name = $_FILES['image']['name'];
                                $size = $_FILES['image']['size'];
                                $tmp_name = $_FILES['image']['tmp_name'];
                                //determine file type//
                                switch($_FILES['image']['type']){
                                    case'image/jpeg':       $ext ="jpg";    break;
                                    case'image/png':        $ext ="png";    break;
                                    default:                $ext ='';       break;
                                }
                                if($ext){
                                    if($size >30000){
                                            $n="$name";
                                            $n= ereg_replace("[^A-Za-z0-9.]","",$n);
                                            $n= strtolower($n);
                                            $n="/uploaded_images/$n";
                                            move_uploaded_file($tmp_name,$n);
                                            echo "<p>Uploaded image'$name' as '$n':</p>";
                                            echo "<img src='$n'/>";
                                    }
                                    else echo "<p>'$name' is too big - 3MB Max(30,000bytes).</p>";
                                }
                                else echo "<p>'$name' is an invalid file - only jpg and png accepted.</p>";
                                }
                                    else echo "<p>No image uploaded. </p>";
                                                                if($cuisine=="") {
                                                                    $query = "INSERT INTO `recipename` (mealname,ingredients,hours,minutes,recipe,imagepath,userid,b_l_d,feeds,cuisine_type) VALUES ('$mealname', '$ingredients','$hours','$minutes','$recipe','$n','$userid','$meal','$feeds','$dropoption')"; 
                                                                    mysqli_query($db_server, $query) or
                                                                    die("Insert failed: " . mysqli_error($db_server)) ;
                                                                    }else{
                                                                            $query = "INSERT INTO`recipename`(mealname,ingredients,hours,minutes,recipe,imagepath,userid,b_l_d,feeds,cuisine_type)VALUES('$mealname', '$ingredients','$hours','$minutes','$recipe','$n','$userid','$meal','$feeds','$cuisine')";
                                                                            mysqli_query($db_server, $query) or
                                                                            die("Insert failed: " . mysqli_error($db_server)) ; 
                                                                            $query = "INSERT INTO `Nation` (cuisine_type) VALUES ('$cuisine')";
                                                                            mysqli_select_db($db_server, $db_database);
                                                                            mysqli_query($db_server, $query) or
                                                                            die("Insert failed: " . mysqli_error($db_server)) ; 
                                                                }
                                        }   
                                        $message = "<strong>Recipe Uploaded!</strong>";             
                                    }
                                    mysqli_free_result($result);
                                }


?>

---

我刚刚解决了这个问题，我不得不将结果页面上的输出更改为：

$mealpic .="<img src='http://ml11maj.icsnewmedia.net/Workshops/Week%207/".$row['imagepath']."'/>"; 

$mealpic.=”；

从

$mealpic.=”；
看起来您正在将图像移动到/upload\u images/文件夹，并从/显示。您上传的图片是否设置为文档根目录？或者您应该尝试将img src设置为/uploaded_images/$n？该文件夹就是图像所在的位置，但我不确定如何设置？您可能需要首先了解如何指定正确的相对路径。图像文件位于php脚本所在的位置？除非您的php文件位于/uploaded_图像中，否则您需要指定相对于php脚本的文件夹。在写入数据库之前，将该相对文件夹路径放入$n。上载的图像文件夹与php文件位于同一文件夹中，并且图像位于该文件夹中。因此，为了使文件夹路径相对，我必须执行//上载的图像/$n？move\u上载的文件函数中有什么内容？这是绝对路径，很高兴它最终能够工作。您可能需要花一些时间来弄清楚如何在HTML中指定文件路径。
$mealpic .="<img src='http://ml11maj.icsnewmedia.net/Workshops/Week%207/".$row['imagepath']."'/>"; 

 $mealpic .="<img src=".$row['imagepath']."/>";